我有一个熊猫DataFrame如下所示。
df
A B
date_time
2014-07-01 06:03:59.614000 62.1250 NaN
2014-07-01 06:03:59.692000 62.2500 NaN
2014-07-01 06:13:34.524000 62.2500 241.0625
2014-07-01 06:13:34.602000 62.2500 241.5000
2014-07-01 06:15:05.399000 62.2500 241.3750
2014-07-01 06:15:05.399000 62.2500 241.2500
2014-07-01 06:15:42.004000 62.2375 241.2500
2014-07-01 06:15:42.082000 62.2375 241.3750
2014-07-01 06:15:42.082000 62.2375 240.2500我想把这个频率改变为有规律的1 minute间隔。但是,请在下面获得错误:
new = df.asfreq('1Min')
>>error: cannot reindex from a duplicate axis现在,我明白为什么会这样了。由于我的时间粒度很高(以毫秒为单位),但不规则,所以我每分钟获得多个读数,甚至每秒都是如此。所以我试着把这些毫秒读数和几分钟结合起来,然后去掉下面的复制件。
# try to convert the index to minutes and drop duplicates
df['index'] = df.index
df['minute_index']= df['index'].apply( lambda x: x.strftime('%Y-%m-%d %H:%M'))
df.drop_duplicates(cols = 'minute_index', inplace = True, take_last = True)
df_by_minute = df.set_index('minute_index')
df_by_minute
A B index
minute_index
2014-07-01 06:03 62.2500 NaN 2014-07-01 06:03:59.692000
2014-07-01 06:13 62.2500 241.50 2014-07-01 06:13:34.602000
2014-07-01 06:15 62.2375 240.25 2014-07-01 06:15:42.082000
# now change the frequency to 1 minute but I just get NaNs (!)
df_by_minute.asfreq('1Min')
A B index
2014-07-01 06:03:00 NaN NaN NaT
2014-07-01 06:04:00 NaN NaN NaT
2014-07-01 06:05:00 NaN NaN NaT
2014-07-01 06:06:00 NaN NaN NaT
2014-07-01 06:07:00 NaN NaN NaT
2014-07-01 06:08:00 NaN NaN NaT
2014-07-01 06:09:00 NaN NaN NaT
2014-07-01 06:10:00 NaN NaN NaT
2014-07-01 06:11:00 NaN NaN NaT
2014-07-01 06:12:00 NaN NaN NaT
2014-07-01 06:13:00 NaN NaN NaT
2014-07-01 06:14:00 NaN NaN NaT
2014-07-01 06:15:00 NaN NaN NaT如你所见,它不起作用。有人能帮忙吗?我试图实现的是获得一个返回A or B as of DateTime和DateTime的函数,该函数将以1分钟递增。
发布于 2014-10-13 16:52:11
我认为,不是asfreq,而是resample适合您的需要:
new = df.resample('T', how='mean')对于how选项,也可以使用“最后”或“第一”。
发布于 2022-05-24 21:16:37
变换数据帧的Pandas Dataframe.resample()函数具有将时间频率从秒变到分钟、小时、日、年等功能,它与DatetimeIndex字段和datetime列完美地工作。



https://stackoverflow.com/questions/26342713
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