搜索3d阵列

Question

我需要帮助输入一个搜索数组。我尝试了一个二进制搜索，但我无法让它工作。其他一切都会正常工作，直到我将正在搜索的值放到数组中，然后它就崩溃了。

它应该如何工作:输入两个坐标，每个坐标都有一个值，然后计算它们之间的距离，然后让用户搜索坐标，如果找到它所在的坐标的话。

谢谢

#include "stdafx.h"
#include <iostream>
#include <iomanip>  //for setprecision
#include <math.h>
#include <cstdbool>
#include <cstdlib>  // Needed for rand and srand
#include <ctime>    // Needed for the time function


using namespace std;


//Function Prototypes
void processThroughArray(int[][10][10], int, int, int, int, int, int);
int searchArray(int[][10][10], int, int, int, int, int, int, int, int);
const int SIZE = 10;

int main()
{

// establish array and set all values to 0
int myArray[10][10][10] = { 0 };

// establish x and y position markers
int x = 0;
int y = 0;
int z = 0;
int x2 = 0;
int y2 = 0;
int z2 = 0;


// establish input for x and y from the user
int xInput = 0;
int yInput = 0;
int zInput = 0;
int xInput2 = 0;
int yInput2 = 0;
int zInput2 = 0;

// variable for value entered
int inputValue = 0;
int inputValue2 = 0;
double distance = 0;
int searchValue;
int result;


// Get the user's value and coordinate
cout << "\nPlease enter the x coordinate ";
cin >> xInput;
cout << "\nPlease enter the y coordinate ";
cin >> yInput;
cout << "\nPlease enter the z coordinate ";
cin >> zInput;


cout << "\nPlease enter the value to place in " << xInput << "," << yInput << "," << zInput << " ";
cin >> inputValue;

// Get the user's ending value and coordinate
cout << "\nPlease enter the ending x coordinate ";
cin >> xInput2;
cout << "\nPlease enter the ending y coordinate ";
cin >> yInput2;
cout << "\nPlease enter the ending z coordinate ";
cin >> zInput2;


cout << "\nPlease enter the value to place in " << xInput2 << "," << yInput2 << "," << zInput2 << " ";
cin >> inputValue2;

// place the value in the coordinate
myArray[xInput][yInput][zInput] = inputValue;
cout << "\nYou have successfully placed the value " << inputValue << " in coordinate " << xInput << ", " << yInput << ", " << zInput << " ";

myArray[xInput2][yInput2][zInput2] = inputValue2;
cout << "\nYou have successfully placed the value " << inputValue2 << " in coordinate " << xInput2 << ", " << yInput2 << ", " << zInput2 << " ";

//Function performing for loop
processThroughArray(myArray, x, y, z, x2, y2, z2);

//calculate distance between the two coordinates
distance = sqrt(pow(xInput2 - xInput, 2.0) + pow(yInput2 - yInput, 2.0) + pow(zInput2 - zInput, 2.0));
cout << "\nThe distance between " << xInput << "," << yInput << "," << zInput << " and " << xInput2 << "," << yInput2 << "," << zInput2 << " is ";
cout << setprecision(4) << distance << endl;


// indicate end of array processing
cout << "\nArray Processed" << endl;

//User inputs value to search for
cout << "Enter the value you wish to look for: ";
cin >> searchValue;

result = searchArray(myArray, SIZE, searchValue, x, y, z, x2, y2,z2);

//If results contains a -1 the value not found

if (result == -1 )
{
    cout << "That number does not exists in the array.\n";
}

else 
{
    cout << "\nValue " << searchValue;
    cout << " is located at position: " << result << endl;

}




system("pause");
return 0;
}


//**************************************************************************
// Definition of function processThroughArray: Process through the array   *
//the for loop                                                             *
//**************************************************************************
void processThroughArray(int myArray[][10][10], int x, int y, int z, int x2, int y2, int z2)
{

for (int x = 0, x2 = 0; x<10, x2 < 10; x++, x2++)
{
    for (int y = 0, y2 = 0; y<10, y2 < 10; y++, y2++)

    {
        for (int z = 0, z2 = 0; z< 10, z2 < 10; z++, z2++)
        {

            // Display the value of the coordinate
            cout << "\nCordinate " << x << ", " << y << ", " << z << " value is " << myArray[x, x2][y, y2][z, z2];

        }
    }
}



}

//**************************************************************************
// Definition of function searchArray: search array for the value input    *
//                                                                         *
//**************************************************************************
int searchArray(int myArray[][10][10], int size, int value,int x, int y, int z, int x2, int y2, int z2)
{
int index = 0;
int position = -1;
bool found = false;


while (index < size && !found)
{
    if (myArray[index][index][index] == value)
    {
        found = true;
        position = index;

    }
    index++;

} 

return position;
}

Answer 1

您将SIZE定义为1000，并将其传递给searchArray()：

const int SIZE = 1000;

// ...

searchArray(myArray, SIZE, searchValue);

您正在searchArray()中执行以下操作：

int searchArray(int myArray[][10][10], int size, int value)
{
    int first = 0,
        last = size - 1,

因为size是1000，所以您将"first“设置为0，将"last”设置为999。

然后，您将执行以下操作(遗漏一些不相关的内容)：

middle = (first + last) / 2;
if (myArray[middle][middle][middle] = value)

所以，让我们拿出一张纸和一支铅笔。因为“第一”为0，“最后”为999，这将“中间”设置为449。

因此，我们这里有两个问题：

1)使用"=“运算符进行赋值，而不是使用"==”进行比较，这似乎是您的意图。

2)将值赋值给myArray449449。不幸的是，您的数组要小得多：

int myArray[10][10][10] = { 0 };

尝试访问由10个元素组成的第449个数组的449个元素，由10个元素组成的第449个数组，并不能很好地工作。即使您正在进行比较或分配某些内容，这都是未定义的行为，而且几乎可以保证崩溃。