我有这个:
# A simple "script" that receives an index
ScriptR = function(i) {
A = i^3;
};
# With "for", pass the index "i" for "ScriptR"
for (i in 1:10) {
ScriptR(i);
};
# How do I pass the index "i" for "ScriptR" function ??
mclapply(1:10, ScriptR, mc.set.seed = FALSE);如何传递"ScriptR“函数的索引"i”??
Tks
发布于 2014-09-30 03:57:14
您的代码应该工作得很好。因为您的函数ScriptR只有一个参数(即i),所以当您调用mclapply(1:10, ScriptR, mc.set.seed = FALSE)时,数字1:10将作为参数传递给ScriptR。如果您想要更明确,您可以调用mclapply(1:10, function(i) ScriptR(i), mc.set.seed = FALSE),但在这种情况下,实际上不需要这样做。
https://stackoverflow.com/questions/26112376
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