SpringMVC -以形式显示对象:选项

Question

嗨，我完全是一个移动背景，所以春天对我来说是新的，我现在有一个名为BusinessForm的表单，这里是内容

public class BusinessForm 
{
 private String selectedBusinessId; //getters and setters included
 private List businessNameList; //getters and setters included - list of Business class Objects
  private List businessIdList; //getters and setters included  - lisy of Business class Objects
//Business class defined below 
}

这是我的控制器

@Controller 
public class HomeController{
    @RequestMapping(value = "/showHome", method = RequestMethod.GET)
    @ExceptionHandler({CutsomException.class})
    public ModelAndView showHome()
    {
         //Init BusinessForm class, its defined above...
         //set values of businessNameList...
         //set values of businessIdList...
         BusinessForm businessForm = new BusinessForm();
         businessForm.setBusinessNameList(....);
         businessForm.setBusinessIdList(....);
         return ModelAndView("MyView","businessForm", businessForm)
    }
}

这是我的观点(我只会显示表格，以避免显示其他人)

MyView.jsp

<form:form action="blah" method="post" modelAttribute="businessForm">
<form:select path="selectedBusinessId">
<form:option value="">Select ID</form:option>
<form:options items="${businessForm.businessIdList}" item/>
</form:select>              
</form:form>

现在我看到的是表单的代码:options items属性是" Business“对象的列表，业务对象具有私有变量businessName和businessId以及getter和setters。

public class Business
{
  private String businessId; //with getters and setter 
  private String businessName; //with getters and setters 
}

因此，在上面的表单中，一旦我打开下拉列表，它实际上向我显示了一个列表，但是该字符串只不过是Business的toString()函数。所以我的下拉项目看起来像com.xxx.Business@c291000。Wihtout覆盖toString()的Business，如何使我的表单在表单列表下拉列表中显示实际的businessId。原因是我想获得另一个表单:选择并显示另一个businessName列表。请帮帮忙。谢谢。

Answer 1

你需要改变你的

<form:select path="selectedBusinessId">
    <form:option value="">Select ID</form:option>
    <form:options items="${businessForm.businessIdList}" item/>
</form:select>

至

<form:select path="selectedBusinessId">
    <form:option value="">Select ID</form:option>
    <form:options items="${businessForm.businessIdList}" itemValue="businessId" itemLabel="businessName" />
</form:select>