给定bash的远程代码执行漏洞于2014年9月24日宣布,如何使用Ansible更新基于apt的系统?
发布于 2014-09-24 19:01:40
这里是我最喜欢的解决方案,在一个相当均匀的环境中。这样做的好处是,与其他人使用的version=latest模式不同,将来更新不会花费太多时间。
- name: update apt cache if not done today
apt: update_cache=yes cache_valid_time=86400
# http://seclists.org/oss-sec/2014/q3/650
- name: ensure secure ansible, ubuntu 1204 edition
apt: pkg=bash=4.2-2ubuntu2.5 state=present
when: ansible_distribution=='Ubuntu' and ansible_distribution_version=='12.04'
- name: ensure secure ansible, ubuntu 1404 edition
apt: pkg=bash=4.3-7ubuntu1.3 state=present
when: ansible_distribution=='Ubuntu' and ansible_distribution_version=='14.04'
# based on the following gist and comments below. there have been several exploits, this covers them well.
# https://gist.github.com/kacy/2b9408af04c71fab686e
- name: ensure bash is not vulnerable to 201409 problem
shell: "foo='() { echo not patched; }' bash -c foo"
register: command_result
ignore_errors: yes
failed_when: "'command not found' not in command_result.stderr"说明:如果每天更新很多次的话,更新apt缓存是很昂贵的。可以调整缓存时间。代码实际上是测试以确保漏洞是固定的-测试是好的。这将突出显示任何未被编码的发行版/版本所涵盖的主机。
用户@jarv 发布了一个很好的解决方案也是如此。而不是总是更新apt,它只在问题没有得到解决的情况下才这样做。这是最快的解决方案(至少在这个答案中)。jarv也有在链接回购中添加了分发测试。,对于异构环境很有用。
- name: Check if we are vulnerable
shell: executable=/bin/bash env x='() { :;}; echo vulnerable' bash -c "echo this is a test"
register: test_vuln
- name: Apply bash security update if we are vulnerable
apt: name=bash state=latest update_cache=true
when: "'vulnerable' in test_vuln.stdout"
- name: Check again and fail if we are still vulnerable
shell: executable=/bin/bash env x='() { :;}; echo vulnerable' bash -c "echo this is a test"
when: "'vulnerable' in test_vuln.stdout"
register: test_vuln
failed_when: "'vulnerable' in test_vuln.stdout"还有其他的方法。Ansible的创建者Michael DeHaan和官方@ansible账户在推特上发布了几个解决方案:
ansible all -m apt -a 'update_cache=yes name=bash state=latest'- name: update apt
command: apt-get update
- name: update bash
command: apt-get --only-upgrade install bash
- name: check bash fix
command: env x='() { :;}; echo vulnerable' bash -c "echo this is a test"
register: command_result
failed_when: "'error' not in command_result.stderr"https://stackoverflow.com/questions/26024468
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