从CellSignalStrength获得NeighboringCellInfo

Question

我需要从CellSignalStrength.getLevel()得到信号电平

我是从CellInfoGsm拿来的

TelephonyManager telephonyManager = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE);
CellInfo allCellInfo = (CellInfo) telephonyManager.getAllCellInfo().get(0);
CellSignalStrength cellSignalStrength = ((CellInfoGsm) allCellInfo).getCellSignalStrength();
int level = cellSignalStrength.getLevel();

但是在某些设备上，我从telephonyManager.getAllCellInfo()中获得null，所以android文档说我使用telephonyManager.getNeighboringCellInfo()。

有没有任何方法从CellSignalStrength或“用户友好”信号级别从NeighboringCellInfo获得？

Answer 1

我通过从getLevel()重写CellInfoGsm函数来解决它--我想我是这样做的。

我调用NeighboringCellInfo.getRssi()，然后将其转换为级别，就像CellInfoGsm.getLevel()做的那样

for(NeighboringCellInfo nci:telephonyManager
                    .getNeighboringCellInfo()){
                if(neighborCellInfo == null) {
                    neighborCellInfo = nci;
                } else if(nci.getRssi() > neighborCellInfo.getRssi()) {
                    neighborCellInfo = nci;
                }
            }

            int level;

            int GSM_SIGNAL_STRENGTH_GREAT = 12;
            int GSM_SIGNAL_STRENGTH_GOOD = 8;
            int GSM_SIGNAL_STRENGTH_MODERATE = 8;

            // ASU ranges from 0 to 31 - TS 27.007 Sec 8.5
            // asu = 0 (-113dB or less) is very weak
            // signal, its better to show 0 bars to the user in such cases.
            // asu = 99 is a special case, where the signal strength is unknown.
            int asu = neighborCellInfo.getRssi();
            if (asu <= 2 || asu == 99) level = 0;
            else if (asu >= GSM_SIGNAL_STRENGTH_GREAT) level = 4;
            else if (asu >= GSM_SIGNAL_STRENGTH_GOOD)  level = 3;
            else if (asu >= GSM_SIGNAL_STRENGTH_MODERATE)  level = 2;
            else level = 1;