运动员运动(跳跃问题)

Question

所以，我试图实现触发游戏中主角移动的键。这是我的代码：

public class Play  implements Screen{

变量：

World world;
Box2DDebugRenderer b2Dr;
OrthographicCamera camera;
OrthographicCamera hudCamera;
private SpriteBatch batch;
private Body toniBody;
private RHContactListener rhcl;

呈现内容(请注意，我有一个名为InputController的java类，用于setInputProcessor，它扩展了InputAdapter，并为Down状态设置了某些键)：

@Override
public void render(float delta) {
    Gdx.gl.glClearColor(1, 1, 1, 1);
    Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT);

    Gdx.input.setInputProcessor(new InputController());
    RHInput.update();
    camera.update();
    handleInput();
    world.step(delta, 6, 2);


    batch.setProjectionMatrix(camera.combined);
    batch.begin();
    batch.end();

    b2Dr.render(world, camera.combined);
}

这里是摄像机设置为特定缩放的地方。

@Override
public void resize(int width, int height) {

    camera.viewportWidth = width/24;
    camera.viewportHeight = height/24;
    camera.update();

}

屏幕上要显示的东西：

@Override
public void show() {
    world = new World(new Vector2(0, -9.81f),true);
    rhcl = new RHContactListener();
    world.setContactListener(rhcl);
    b2Dr  = new Box2DDebugRenderer();

    batch = new SpriteBatch();
    camera= new OrthographicCamera();

在这里，我定义了我的场景、地面和玩家的对象：

    ////Box2D////

    //CREATE GROUND
    //body definition
    BodyDef bDef = new BodyDef();
    bDef.position.set(0,-14);//meters
    bDef.type = BodyDef.BodyType.StaticBody;
    Body body = world.createBody(bDef);
    //shape definition
    PolygonShape ground = new PolygonShape();
    ground.setAsBox(25, 1);//meters
    //fixture definition
    FixtureDef fDef = new FixtureDef();
    fDef.friction= .5f;
    fDef.shape = ground;
    fDef.filter.categoryBits = B2DVariables.BIT_ground;//colision type
    fDef.filter.maskBits = B2DVariables.BIT_can;//matching collision type
    body.createFixture(fDef).setUserData("ground");

    //CREATE TONI
    //body definition
    bDef.position.set(-10,-10);//meters
    bDef.type = BodyDef.BodyType.DynamicBody;
    toniBody = world.createBody(bDef);
    //shape definition
    PolygonShape tBox = new PolygonShape();
    tBox.setAsBox(0.5f,2);//meters
    //fixture definition
    fDef.shape = tBox;
    fDef.filter.categoryBits = B2DVariables.BIT_can;//colision type can step on ground
    fDef.filter.maskBits = B2DVariables.BIT_ground;
    toniBody.createFixture(fDef).setUserData("toni");

    //Toni's foot the Ground Sensor
    tBox.setAsBox(.2f , 0.2f, new Vector2(0, -2),0);
    fDef.shape = tBox;
    fDef.filter.categoryBits = B2DVariables.BIT_can;
    fDef.filter.maskBits = B2DVariables.BIT_ground;
    fDef.isSensor = true;
    toniBody.createFixture(fDef).setUserData("toniFoot");

    ground.dispose();
    tBox.dispose();
}

这是一个特定的键触发动作的部分

public  void handleInput(){

    //press W key aka Up key or BTNup
    if (RHInput.isDown(RHInput.BTNup)){

        if(rhcl.isPlayerOnGround()) {
            toniBody.setLinearVelocity(0,100);
            System.out.println("Toni jumps");
        }
    }


    if (RHInput.isDown(RHInput.BTNright)){
        rhcl.isPlayerOnGround();
        toniBody.setLinearVelocity(5,0);
        System.out.println("Toni walks right");
    }else {

        toniBody.setLinearVelocity(0,0);
    }


    if (RHInput.isDown(RHInput.BTNleft)){

        if(rhcl.isPlayerOnGround()) {
            toniBody.setLinearVelocity(-5,0);
            System.out.println("Toni walks left");
        }
        else {

            toniBody.setLinearVelocity(0,0);
        }
    }

            if (RHInput.isPressed(RHInput.BTNdown)){
        System.out.println("pressed s");
    }
    if (RHInput.isDown(RHInput.BTNdown)){
        System.out.println("holding s");
    }
}

其他libGDX材料

@Override
public void hide() {
    dispose();
}

@Override
public void pause() {

}

@Override
public void resume() {

}

@Override
public void dispose() {
    world.dispose();
    b2Dr.dispose();
}

}

密码有效了。字符以线性速度向左和向右移动。但是它不会跳得很高，当它掉下来的时候，它会很慢地掉下来。怎么才能解决这个问题？

谢谢!

Answer 1

好吧..。我从未使用过libgdx，但我一直在阅读如何在这里实现跳转( http://obviam.net/index.php/getting-started-in-android-game-development-with-libgdx-tutorial-part-3-jumping-gravity-and-movement/ )，并检查您添加的物理代码。我看到你有太多的摩擦(如.5左右)，所以雪碧应该是漂浮的。当重力在世界构造函数中为9.8m/秒^2时，它以每秒5米的速度跳跃，所以它会在一秒内减速所以，消除摩擦，想象一下，就像在教程中一样。