Android环境下AM/PM时间的比较

Question

我有个方案

start-time = 4:15 PM
end-time = 2:00 AM 

如果我的current-time (假设晚上9:15以与开始或结束时间相同的格式)介于start-time和end-time之间，那么goto screen 1是其他明智的goto screen 2

我的问题是如何比较current-time更大或等于‘开始时间’和更少或等于‘结束时间’。我尝试过将给定的时间值转换为milliseconds并进行比较，但current-time = 9:15 PM似乎大于“结束时间= 2:00 AM”，因为2:00的时间将在午夜后到来，如果‘9:15下午=周四，那么2:00将是星期五’。我找了很多东西，但还是想不出来。任何类型的帮助都将不胜感激。

编辑：

当前时间、启动时间和结束时间--所有被视为String的值

编辑2

密码：

long currentTime = getMillis("9:15 PM");

long startTime = getMillis("4:15 PM");

long endTime = getMillis("2:00 AM");//this will be the next day's time confusing part for me

if(currentTime >= startTime && currentTime <= endTime)
{
   //goto screen 1
}
else
{
  // goto screen 2
}


private long getMillis(String givenTime)
{
   SimpleDateFormat sdf = new SimpleDateFormat("h:mm a");
try {
    Date mDate = sdf.parse(givenTime);
    long timeInMilliseconds = mDate.getTime();
    System.out.println("Date in milli :: " + timeInMilliseconds);
    return timeInMilliseconds;
} catch (ParseException e) {
            e.printStackTrace();
}
return 0;
}

Answer 1

步骤1:，您只需将一天添加到您的结束时间，当它低于您的开始时间。

步骤2: 应用条件检查当前时间是否介于开始时间和结束时间之间

    try {
        Date mToday = new Date();

        SimpleDateFormat sdf = new SimpleDateFormat("hh:mm aa");
        String curTime = sdf.format(mToday);
        Date start = sdf.parse("4:15 PM");
        Date end = sdf.parse("2:00 AM");
        Date userDate = sdf.parse(curTime);

        if(end.before(start))
        {
            Calendar mCal = Calendar.getInstance();
            mCal.setTime(end);
            mCal.add(Calendar.DAY_OF_YEAR, 1);
            end.setTime(mCal.getTimeInMillis());
        }

        Log.d("curTime", userDate.toString());
        Log.d("start", start.toString());
        Log.d("end", end.toString());


        if (userDate.after(start) && userDate.before(end)) {
            Log.d("result", "falls between start and end , go to screen 1 ");
        }
        else{
            Log.d("result", "does not fall between start and end , go to screen 2 ");
        }
    } catch (ParseException e) {
        // Invalid date was entered
    }

Answer 2

试试这个：

Date dt = new Date();
SimpleDateFormat sdf = new SimpleDateFormat("hh:mm aa");
String curTime = sdf.format(dt);
Date start = parser.parse("4:15 PM");
Date end = parser.parse("2:00 AM");

try {
    Date userDate = parser.parse(curTime);
    if (userDate.after(start)){
      ....
      //you can have your if...else if... conditions 
    }
    if(userDate.before(end)) {
        ....
    }
} catch (ParseException e) {
    // Invalid date was entered
}

Answer 3

使用不带日期或时区的只支持时间值的日期时间库.

在Java世界中，我们有两个很好的日期库：尤达-时间和java.time (由JSR 310定义，与Java 8捆绑在一起，灵感来自Joda-Time )。两个库都提供了一个LocalTime类。

尤达-时间

下面是一些Joda-Time2.4中的未测试的代码，以使您朝着正确的方向前进。

String inputStart = "4:15 PM";
String inputStop = "2:00 AM";

DateTimeFormatter formatter = DateTimeFormat.forPattern( "h:mm a" );
LocalTime start = formatter.parseLocalTime( inputStart );
LocalTime stop = formatter.parseLocalTime( inputStop );
String now = LocalTime.now( DateTimeZone.forID( "America/Montreal" ) );

boolean isNowInRange = false;
if( start.isEqual( stop ) ) {
    isNowInRange = ( now.isEqual( start ) );
} else if ( start.isBefore( stop ) ) {
    isNowInRange = ( ( now.isEqual( start ) || now.isAfter( start ) ) && now.isBefore( stop ) );
} else if ( start.isAfter( stop ) ) {
    isNowInRange = ( ( now.isEqual( start ) || now.isAfter( start ) ) || now.isBefore( stop ) );
} else {
    // FIXME: Handle this supposedly impossible case.
}