如何将HttpRouter与MuxChain结合使用？

Question

我想在保持路由参数(如赫普鲁特 )的同时，在多链中使用/:user/。

以下列例子为例：

func log(res http.ResponseWriter, req *http.Request) {
  fmt.Println("some logger")
}

func index(res http.ResponseWriter, req *http.Request) {
  fmt.Fprintf(res, "Hi there, I love %s!", req.URL.Path[1:])
}

func main() {
  logHandler := http.HandlerFunc(log)
  indexHandler := http.HandlerFunc(index)
  chain := muxchain.ChainHandlers(logHandler, indexHandler)
  router := httprouter.New()
  router.Handler("GET", "/:user", chain)
  http.ListenAndServe(":8080", router)
}

当我访问http://localhost:8080/john时，我显然无法访问ps httprouter.Params，这是因为httprouter需要查看httprouter.Handle类型，但是函数是用http.Handler类型调用的。

有没有办法同时使用这两个包？HttpRouter GitHub回购公司说

唯一的缺点是，当使用http.Handler或http.HandlerFunc时，无法检索参数值，因为没有有效的方法来传递带有现有函数参数的值。

Answer 1

如果您强烈希望使用该包，可以尝试这样做：

package main

import (
    "fmt"
    "github.com/gorilla/context"
    "github.com/julienschmidt/httprouter"
    "github.com/stephens2424/muxchain"
    "net/http"
)

func log(res http.ResponseWriter, req *http.Request) {
    fmt.Printf("some logger")
}

func index(res http.ResponseWriter, req *http.Request) {
    p := context.Get(req, "params").(httprouter.Params)
    fmt.Fprintf(res, "Hi there, I love %s!", p.ByName("user"))
}

func MyContextHandler(h http.Handler) httprouter.Handle {
    return func(res http.ResponseWriter, req *http.Request, p httprouter.Params) {
        context.Set(req, "params", p)
        h.ServeHTTP(res, req)
    }
}

func main() {
    logHandler := http.HandlerFunc(log)
    indexHandler := http.HandlerFunc(index)
    chain := muxchain.ChainHandlers(logHandler, indexHandler)
    router := httprouter.New()
    router.GET("/:user", MyContextHandler(chain))
    http.ListenAndServe(":8080", router)
}