如何监视nodejs模块中的类方法

Question

我有一个导出类的简单模块：

function PusherCom(options) {
}

PusherCom.prototype.lobbyEvent = function(event, message) {
};

module.exports = PusherCom;

我需要我的./index.js

var PusherCom = require('../comms/pusher');

function Play() {
  var pusher = new PusherCom();
  pusher.lobbyEvent('event', {});
}

我对这个应用程序进行了测试，问题是如何模拟require('../comms/pusher')类，或者仅仅模拟lobbyEvent方法。最好是一个罪恶的间谍，这样我就可以断言lobbyEvent的论点了。

describe 'playlogic', ->

  beforeEach, ->
    pushMock = ->
      @lobbyEvent = (event, message) ->
        console.log event
      @
    // currently I tried proxyquire to mock the require but it doesn't support spying
    proxyquire './index.js, { './comms/pusher': pushMock }

  it 'should join lobby', (done) ->
    @playLogic = require './index.js'
    @playLogic.joinedLobby {}, (err, result) ->
      // How can I spy pushMock so I can assert the arguments
      // assert pushMock.called lobbyEvent with event, 'event'

如何在nodejs中任意模块中的类中模拟/监视方法？

Answer 1

我不是javascript专家，但我还是会冒险的。与其监视模块，不如在pusher实例的pusher方法中执行它，并将其注入Play()中，这对于您的情况来说是一个合理的解决方案吗？例如：

// pusher.js
function PusherCom(options) { }

PusherCom.prototype.lobbyEvent = function(event, message) { };

module.exports = PusherCom;


// play.js
function Play(pusher) {
  pusher.lobbyEvent("event", { a: 1 });
}

module.exports = Play;

// play_test.js
 var assert    = require("assert"),
     sinon     = require("sinon"),
     PusherCom = require("./pusher"),
     Play      = require("./play");

describe("Play", function(){
  it("spy on PusherCom#lobbyEvent", function() {
    var pusher = new PusherCom(),
        spy    = sinon.spy(pusher, "lobbyEvent");

    Play(pusher);

    assert(spy.withArgs("event", { a: 1 }).called);
  })
})

哈哈！