我用AWS上传到我的桶里的图片是这样的:
BFTask *task = [BFTask taskWithResult:nil];
[[task continueWithBlock:^id(BFTask *task) {
self.URL = [NSURL fileURLWithPath:[NSTemporaryDirectory() stringByAppendingPathComponent:@"test"]];
NSData *data = UIImagePNGRepresentation(image);
//NSMutableString *dataString = [NSMutableString new];
[data writeToURL:self.URL atomically:YES];
return nil;
}]continueWithExecutor:[BFExecutor mainThreadExecutor] withBlock:^id(BFTask *task) {
self.uploadRequest1 = [AWSS3TransferManagerUploadRequest new];
self.uploadRequest1.bucket = S3BucketName;
self.uploadRequest1.key = S3KeyUploadName1;
self.uploadRequest1.body = self.URL;
return nil;
}];
AWSS3TransferManager *transferManager = [AWSS3TransferManager defaultS3TransferManager];
[[transferManager upload:self.uploadRequest1] continueWithExecutor:[BFExecutor mainThreadExecutor] withBlock:^id(BFTask *task) {
if (task.error != nil) {
if( task.error.code != AWSS3TransferManagerErrorCancelled
&&
task.error.code != AWSS3TransferManagerErrorPaused
)
{
NSLog(@"Upload Failed!");
}
} else {
self.uploadRequest1 = nil;
NSLog(@"Uploaded!");
}
return nil;
}];上传图像的代码工作得很好。当我打开我的桶,我看到那里的图像。
现在,我想要做的是获取该图像的URL,有什么方法可以获得URL而不必再次获取图像呢?
发布于 2014-09-08 14:35:18
你不明白,你创造它就像:
发布于 2015-06-13 06:58:16
AWSS3TransferManagerUploadRequest *uploadRequest = [AWSS3TransferManagerUploadRequest new];
uploadRequest.body = [NSURL fileURLWithPath:filePath];
uploadRequest.key = fileName;
uploadReuest.bucket = S3BucketName;uploadRequest setACL:AWSS3ObjectCannedACLPublicRead;
上面的答案是正确的,但您必须将"ACL“设置为uploadRequest。
在你的问题中,你忘了设置"ACL“。
谢谢
发布于 2016-06-08 07:05:50
我能够从亚马逊的S3 -> Bucket ->文件夹->图像文件->属性获得路径,在右边,您将看到这样的情况。

https://stackoverflow.com/questions/25726720
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