处理Jackson异常

Question

我用球衣做了一个休息，我试着处理异常。我注册了jackson如何默认使用这个类来执行与json映射有关的所有操作：

@javax.ws.rs.ApplicationPath("/")
public class MyApplication extends ResourceConfig {
   public MyApplication() {
       packages("controller");
       register(JacksonFeature.class);       
   }
}

我定义了一个异常映射程序来捕获一些异常，例如使用以下类的"UnauthorizedException“和"BadRequestException”：

@Provider
public class ClientExceptionMapper implements ExceptionMapper<BaseException>
{
    @Override
    public Response toResponse(BaseException ex) 
    {
        System.out.println("qwertweryt");
        if(ex instanceof UnauthorizedException)
        {
            System.out.println("Unauthorized!");
            return (((UnauthorizedException)ex).getResponse());
        }
        else if(ex instanceof BadrequestException)
        {
            System.out.println("Badrequest!");
            return (((BadrequestException)ex).getResponse());
        }
        return null;
    }
}

其中BaseException、UnauthorizedException和BarequestException分别为：

public abstract class BaseException extends WebApplicationException
{
    private Response r;

    public BaseException(Response response)
    {
        r = response;
    }

    public Response getResponse()
    {
        return r;
    }
}

public class UnauthorizedException extends BaseException
{
    public UnauthorizedException(Response response)
    {
        super(response);
    }
}

public class BadrequestException extends BaseException
{
    public BadrequestException(Response response)
    {
        super(response);
    }
}

因此，在处理jackson exceptions...In事实之前，所有操作都很好--我定义了另一个异常映射器，类似于第一个异常映射器，以处理由jackson生成的所有异常(例如，JsonMappingException)，但无法工作。我向您报告我的应用程序所获得的错误：

org.codehaus.jackson.map.exc.UnrecognizedPropertyException: Unrecognized field "serverr" (Class controller.server.control.response.GetServerDetailsResponse), not marked as ignorable
at [Source: org.glassfish.jersey.message.internal.EntityInputStream@701d7463; line: 1, column: 14] (through reference chain: controller.server.control.response.GetServerDetailsResponse["serverr"])
at org.codehaus.jackson.map.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:53)
at org.codehaus.jackson.map.deser.StdDeserializationContext.unknownFieldException(StdDeserializationContext.java:267)
at org.codehaus.jackson.map.deser.std.StdDeserializer.reportUnknownProperty(StdDeserializer.java:673)
at org.codehaus.jackson.map.deser.std.StdDeserializer.handleUnknownProperty(StdDeserializer.java:659)
at org.codehaus.jackson.map.deser.BeanDeserializer.handleUnknownProperty(BeanDeserializer.java:1365)
at org.codehaus.jackson.map.deser.BeanDeserializer._handleUnknown(BeanDeserializer.java:725)
at org.codehaus.jackson.map.deser.BeanDeserializer.deserializeFromObject(BeanDeserializer.java:703)
at org.codehaus.jackson.map.deser.BeanDeserializer.deserialize(BeanDeserializer.java:580)
at org.codehaus.jackson.map.ObjectMapper._readValue(ObjectMapper.java:2704)
at org.codehaus.jackson.map.ObjectMapper.readValue(ObjectMapper.java:1315)
at org.codehaus.jackson.jaxrs.JacksonJsonProvider.readFrom(JacksonJsonProvider.java:419)
at org.glassfish.jersey.message.internal.ReaderInterceptorExecutor$TerminalReaderInterceptor.aroundReadFrom(ReaderInterceptorExecutor.java:181)
at org.glassfish.jersey.message.internal.ReaderInterceptorExecutor.proceed(ReaderInterceptorExecutor.java:134)
at org.glassfish.jersey.server.internal.MappableExceptionWrapperInterceptor.aroundReadFrom(MappableExceptionWrapperInterceptor.java:72)
at org.glassfish.jersey.message.internal.ReaderInterceptorExecutor.proceed(ReaderInterceptorExecutor.java:134)

我的第一个问题是:这两个类可能会发生冲突，即在同一个项目中没有两个例外映射器吗？第二个问题是，我如何解决这个问题？我希望我已经说清楚了，并提前感谢你的帮助！

嗨，我刚看了一篇文章，它提出了和我一样的问题，我向你报告了这个问题的链接：Jersey: Returning 400 error instead of 500 when given invalid request body。作为第一件事，我尝试在帖子的第一个答案中编写的代码，但是结果与前面相同:当我在请求正文中插入一个错误时，我总是获得500个错误代码，而不是400个。我还尝试将@JsonIgnoreProperties(ignoreUnknown=true)放在处理拦截请求体的类之上，但对我不起作用。

Answer 1

我认为问题在于，您还没有将ExceptionMapper注册到应用程序运行时加载类提供程序中。尝试使用以下代码向其添加mapper类：

   @javax.ws.rs.ApplicationPath("/")
    public class MyApplication extends ResourceConfig {
       public MyApplication() {
           packages("controller");
           register(JacksonFeature.class);
           register(ClientExceptionMapper.class);          
       }
    }

希望它能有所帮助:)