Dill.detect.children对象类型

Question

Dill.detect.children需要两个参数：obj和objtype。

检查一个我可以调用的音频对象：

dill.detect.children(audiofile, object)
dill.detect.children(audiofile, dict)
dill.detect.children(audiofile, list)

没有错误的返回。

但是如何寻找例如的方法呢？

type(audiofile.save)

返回

instancemethod

试过

dill.detect.children(audiofile, instancemethod)

回传

NameError: name 'instancemethod' is not defined

试过

dill.detect.children(audiofile, 'instancemethod')

回传

TypeError: isinstance() arg 2 must be a class, type, or tuple of classes and types

这不应该返回类似于调用dir(audiofile)的结果吗？

Answer 1

使用types.MethodType

types.MethodType 用户定义的类实例的方法类型。

>>> import types
>>> print types.MethodType
<type 'instancemethod'>
>>> p = Process()
>>> type(p.start) == types.MethodType
True

然而，我不认为dill.detect.children会像你想的那样做。它的docstring说：

children(obj, objtype, depth=1, ignore=())
    Find the chain of referrers for obj. Chain will start with obj.

    objtype: an object type or tuple of types to search for
    depth: search depth (e.g. depth=2 is 'grandparents')
    ignore: an object or tuple of objects to ignore in the search

    NOTE: a common thing to ignore is all globals, 'ignore=globals()'

    NOTE: repeated calls may yield different results, as python stores
    the last value in the special variable '_'; thus, it is often good
    to execute something to replace '_' (e.g. >>> 1+1).

这与“在obj上查找与objtype类型匹配的所有属性”是不一样的，这至少是您期望它所做的。