我有一系列SQL命令,这些命令会导致更新当前使用php页面显示的表。
我想在每次加载页面时运行一组sql语句,因为有一个日期字段会不时更新。有人能给我建议一下最好的方法吗?
下面是我当前的页面代码:
$sql = 'SELECT order_item_name, product_quantity,
order_number, category_name
FROM pvz8y_shopping_list';我想包括以下几点:
DROP TABLE pvz8y_shopping_list;
CREATE TABLE pvz8y_shopping_list (
id MEDIUMINT NOT NULL AUTO_INCREMENT,
isle_number int(11),
category_name char(180),
virtuemart_product_id int(11),
virtuemart_category_id int(11),
order_item_name char(255),
product_quantity int(11),
order_number char(64),
PRIMARY KEY (id)
);
INSERT INTO pvz8y_shopping_list (virtuemart_product_id, order_item_name, product_quantity, order_number)
SELECT virtuemart_product_id, order_item_name, product_quantity,order_number from pvz8y_virtuemart_order_items
INNER JOIN pvz8y_virtuemart_orders
ON pvz8y_virtuemart_order_items.virtuemart_order_id = pvz8y_virtuemart_orders.virtuemart_order_id
WHERE pvz8y_virtuemart_orders.created_on **>= '2014-07-19 00:00:00' AND
pvz8y_virtuemart_orders.created_on <= '2014-07-20 00:00:00';**
UPDATE pvz8y_shopping_list
INNER JOIN pvz8y_virtuemart_product_categories ON pvz8y_shopping_list.virtuemart_product_id = pvz8y_virtuemart_product_categories.virtuemart_product_id
SET pvz8y_shopping_list.virtuemart_category_id = pvz8y_virtuemart_product_categories.virtuemart_category_id;
UPDATE pvz8y_shopping_list
INNER JOIN pvz8y_virtuemart_categories_en_gb ON pvz8y_shopping_list.virtuemart_category_id = pvz8y_virtuemart_categories_en_gb.virtuemart_category_id
SET pvz8y_shopping_list.category_name = pvz8y_virtuemart_categories_en_gb.category_name;如您所见,使用sql语句创建shopping_list表,目前只显示结果,但我希望不必每次在日期(粗体更改中突出显示)后端创建表。
发布于 2014-08-12 19:33:32
我不知道你为什么要丢下桌子来创造这个桌子?如果您只想清除表,那么只需使用
TRUNCATE TABLE pvz8y_shopping_list
MySQL有存储过程--您可以使用它来完成您的工作,或者PHP也可以对此进行实时处理,但是必须在CRONTAB中添加脚本。
编辑
定义连接
$hostname_appscon = "localhost";
$database_appscon = "DBNAME";
$username_appscon = "DBUSER";
$password_appscon = "DBPASS";
$appscon = mysql_pconnect($hostname_appscon, $username_appscon, $password_appscon) or trigger_error(mysql_error(),E_USER_ERROR);现在,使用上面定义的连接进行调用,您可以根据需要调用查询。
mysql_query("SQL QUERY1", $appscon);
mysql_query("SQL QUERY2", $appscon);
mysql_query("SQL QUERY3", $appscon);这样,您就可以调用任意多个查询。
https://stackoverflow.com/questions/25272371
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