先进路由Laravel

Question

目前，我有一个在Laravel中构建的简单的Laravel应用程序，它与database of Books交互。这是我的routes.php文件：

Route::model('book', 'Book');

//Show pages
Route::get('/', 'BookController@index');
Route::get('book/create', 'BookController@create');
Route::get('book/edit/{book}', 'BookController@edit');
Route::get('book/delete/{book}', 'BookController@delete');
Route::get('book/view/{book}', 'BookController@view');

//Handle form submissions
Route::post('create', 'BookController@handleCreate');
Route::post('edit', 'BookController@handleEdit');
Route::post('delete', 'BookController@handleDelete');

然后，在我的views文件夹中，我有以下文件：

create.blade.php
edit.blade.php
index.blade.php
layout.blade.php
view.blade.php

Controller是BookController

class BookController extends BaseController {

    //View page - Shows list of books
    public function index(){
        $books = Book::all();
        //compact()creates array of the books using names as keys
        return View::make('index', compact('books'));
    }

    //Create page - Shows create Form
    public function create(){
        return View::make('create');
    }

    //Logic to add a new book to the DB
    public function handleCreate(){
        $book = new Book;
        $book->book_name = Input::get('name');
        $book->book_desc = Input::get('desc');
        $book->save();
        return Redirect::action('BookController@index');
    }

    //Edit page - Shows edit form and populates with book info
    public function edit(Book $book){
        return View::make('edit', compact('book'));
    }

    //Logic to update an existing book in the DB
    public function handleEdit(){
        $book = Book::findOrFail(Input::get('id'));
        $book->book_name = Input::get('name');
        $book->book_desc = Input::get('desc');
        $book->save();
        return Redirect::action('BookController@index');
    }

    //Delete page
    public function delete(Book $book){
        //Show delete confirmation page
        return View::make('delete', compact('book'));
    }

    public function handleDelete(){
        //Handle delete logic...
        $id = Input::get('book');
        $book = Book::findOrFail($id);  
        $book->delete();
        return Redirect::action('BookController@index');
    }

    //View 
    public function view(Book $book){
        return View::make('view', compact('book'));
    }
}

我的问题是，如果我要将不同的views嵌套在一个名为books的子文件夹中，我如何修改我的路由。我尝试创建一个名为books的文件夹，并将views粘贴到其中，当我运行应用程序时，它说它找不到视图。

Answer 1

视图子文件夹

您可以简单地使用点语法在视图文件夹中导航文件夹结构。例如，以索引视图为例，如果要在views\books中使用索引视图，可以这样做：

public function index(){
    $books = Book::all();

    return View::make('books.index', compact('books'));
}

就这样!拉勒维尔把事情做得很简单。

因此，如果我们想更深入地研究这个问题，那么books内部的另一个子文件夹名为travel给予您views\books\travel如何？

public function index(){
    $books = Book::all();

    return View::make('books.travel.index', compact('books'));
}

资源路由

还值得注意的是，Laravel使路由到RESTful控制器(如您的BookController )非常容易使用Route::resource。对方法的所有映射GET和POST请求都是为您完成的。看看这里：http://laravel.com/docs/controllers#resource-controllers