我正在尝试从一系列API调用构建数据框架。每个调用都返回一些JSON,如下所示:
{"ip":"83.108.241.206","country_code":"NO","country_name":"Norway","region_code":"15","region_name":"Sogn og Fjordane","city":"Øvre Ã…rdal","zipcode":"6884","latitude":61.3167,"longitude":7.8,"metro_code":"","area_code":""}我希望将这些调用编译成一个数据框架,其中列为"ip“、”国家代码“等。但是,我很难将每个文件有效地转换成我可以调用rbind的表单。
我使用URL向量进行API调用,如下所示:
> urls <- c("http://freegeoip.net/json/83.108.241.206", "http://freegeoip.net/json/129.118.15.107","http://freegeoip.net/json/189.144.59.71", "http://freegeoip.net/json/24.106.181.190", "http://freegeoip.net/json/213.226.181.3", "http://freegeoip.net/json/84.1.204.89")
> urls
[1] "http://freegeoip.net/json/83.108.241.206"
[2] "http://freegeoip.net/json/129.118.15.107"
[3] "http://freegeoip.net/json/189.144.59.71"
[4] "http://freegeoip.net/json/24.106.181.190"
[5] "http://freegeoip.net/json/213.226.181.3"
[6] "http://freegeoip.net/json/84.1.204.89" 从URL到JSON到数据帧的最佳方法是什么?
发布于 2014-08-07 21:42:17
我正在复制“抄本”,这样您就可以看到中间值和我所犯的一些错误。用几个工具也不难:
> require(RJSONIO) # Used version 1.3-0
> require(downloader) # version 0.3
# probably not necessary but has wider range of url-types it can handle
Loading required package: downloader
> urls <- c("http://freegeoip.net/json/83.108.241.206",
"http://freegeoip.net/json/129.118.15.107",
"http://freegeoip.net/json/189.144.59.71",
"http://freegeoip.net/json/24.106.181.190",
"http://freegeoip.net/json/213.226.181.3",
"http://freegeoip.net/json/84.1.204.89")
>
> download(urls[1], "temp")
100 225 100 225 0 0 1301 0 --:--:-- --:--:-- --:--:-- 2710 0 --:--:-- --:--:-- --:--:-- 0
# Experience tells me to use `quiet=TRUE`
# to prevent bad interactions with my GUI console display
> df <- fromJSON(file("temp")) #### See below for improved strategy ###
> str(df)
List of 11
$ ip : chr "83.108.241.206"
$ country_code: chr "NO"
$ country_name: chr "Norway"
$ region_code : chr "15"
$ region_name : chr "Sogn og Fjordane"
$ city : chr "Øvre Årdal"
$ zipcode : chr "6884"
$ latitude : num 61.3
$ longitude : num 7.8
$ metro_code : chr ""
$ area_code : chr ""
> str(as.data.frame(df))
'data.frame': 1 obs. of 11 variables:
$ ip : Factor w/ 1 level "83.108.241.206": 1
$ country_code: Factor w/ 1 level "NO": 1
$ country_name: Factor w/ 1 level "Norway": 1
$ region_code : Factor w/ 1 level "15": 1
$ region_name : Factor w/ 1 level "Sogn og Fjordane": 1
$ city : Factor w/ 1 level "Øvre Årdal": 1
$ zipcode : Factor w/ 1 level "6884": 1
$ latitude : num 61.3
$ longitude : num 7.8
$ metro_code : Factor w/ 1 level "": 1
$ area_code : Factor w/ 1 level "": 1
> str(as.data.frame(df, stringsAsFactors=FALSE))
'data.frame': 1 obs. of 11 variables:
$ ip : chr "83.108.241.206"
$ country_code: chr "NO"
$ country_name: chr "Norway"
$ region_code : chr "15"
$ region_name : chr "Sogn og Fjordane"
$ city : chr "Øvre Årdal"
$ zipcode : chr "6884"
$ latitude : num 61.3
$ longitude : num 7.8
$ metro_code : chr ""
$ area_code : chr ""所以这就是准备。如果您将这些列作为因素保留,那么它将干扰第一个rbind调用:
df <- as.data.frame( fromJSON(file("temp")) , stringsAsFactors=FALSE)
for ( i in 2:length(urls) ) {download(urls[i], "temp", quiet=TRUE); df <- rbind( df, fromJSON( file("temp") ) )}
> df
ip country_code country_name region_code region_name
df "83.108.241.206" "NO" "Norway" "15" "Sogn og Fjordane"
"129.118.15.107" "US" "United States" "TX" "Texas"
"189.144.59.71" "MX" "Mexico" "09" "Distrito Federal"
"24.106.181.190" "US" "United States" "NC" "North Carolina"
"213.226.181.3" "LT" "Lithuania" "57" "Kauno Apskritis"
"84.1.204.89" "HU" "Hungary" "12" "Komárom-Esztergom"
city zipcode latitude longitude metro_code area_code
df "Øvre Årdal" "6884" 61.3167 7.8 "" ""
"Lubbock" "79409" 33.61 -101.8213 "651" "806"
"Mexico" "" 19.4342 -99.1386 "" ""
"Raleigh" "27604" 35.8181 -78.5636 "560" "919"
"Kaunas" "" 54.9 23.9 "" ""
"Környe" "" 47.5467 18.3208 "" "" 使用stringsAsFactors=FALSE将强制添加到dataframe类可以防止rbind()操作创建列表矩阵,或者在使用因素重新绑定行时遇到问题。
https://stackoverflow.com/questions/25192500
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