通过UIActivityViewController与Twitter/Facebook等共享，造成崩溃

Question

在iOS8上，我使用UIActivityViewController与Facebook/Twitter等共享UIImage。它似乎运转良好，但今天在我的iPad上运行代码时，它突然开始崩溃。但是，在模拟器中，它仍然可以正常工作。

我的代码：

UIActivityViewController *controller =
[[UIActivityViewController alloc]
 initWithActivityItems:@[text, url, myImage]
 applicationActivities:nil];

[self presentViewController:controller animated:YES completion:nil];

一旦崩溃，Xcode就会吐出：

已发现的扩展：{( {id = com.apple.share.Facebook.post}，{id = com.apple.share.Twitter.post}，{id = com.apple.share.TencentWeibo.post}，属性的{id = com.apple.share.SinaWeibo.post} }：{ NSExtensionActivationRule ={ extensionItems =({extensionItems=({ registeredTypeIdentifiers =)( "public.image“)；}，{ registeredTypeIdentifiers =(“public.plain.纯文本”)；{ registeredTypeIdentifiers =( "public.url“)；}；}；}；NSExtensionPointName =( "com.apple.share-services“、"com.apple.ui-services”、"com.apple.services“)；} 2014-08-07 21:38:59.208拼贴测试279:11021 LaunchServices: invalidationHandler称为2014-08-07 21:38:59.212拼贴测试279:11016已发现扩展：{( {id = com.apple.share.Flickr.post}，{id =LaunchServices= com.apple.share.Twitter.post}，{id = com.apple.share.Facebook.post}，{id = com.apple.share.Vimeo.post}，{id = com.apple.share.SinaWeibo.post}，{id = com.apple.share.TencentWeibo.post} )属性：{ NSExtensionPointName = "com.apple.share-services"；} 2014-08-07 21:38:59.216测试279:11021 LaunchServices: invalidationHandler调用

Answer 1

查看医生们，我需要为popover控制器定义一个源视图。

UIActivityViewController *controller =
[[UIActivityViewController alloc]
 initWithActivityItems:@[text,url,myImage]
 applicationActivities:nil];

[self presentViewController:controller animated:YES completion:nil];

UIPopoverPresentationController *presentationController =
[controller popoverPresentationController];

presentationController.sourceView = self.view;

Answer 2

popoverPresentationController是iOS 8的新手，它将在iOS 7上崩溃，在iPhone上也将是零，因为它只出现在UIPopover on iPad中。这是克里斯蒂安在斯威夫特的回答，并考虑到了这些事实：

Swift 2.0 (Xcode 7)

let controller = UIActivityViewController(activityItems: [text, url, myImage], applicationActivities: nil)

presentViewController(controller, animated: true, completion: nil)

if #available(iOS 8.0, *) {
    let presentationController = controller.popoverPresentationController
    presentationController?.sourceView = view
}

Swift 1.2 (Xcode 6)

let controller = UIActivityViewController(activityItems: [text, url, myImage], applicationActivities: nil)

presentViewController(controller, animated: true, completion: nil)

if controller.respondsToSelector("popoverPresentationController") {
    // iOS 8+
    let presentationController = controller.popoverPresentationController
    presentationController?.sourceView = view
}

Answer 3

正如@mmccomb告诉这里的那样，在iPad上，活动视图控制器将使用新的UIPopoverPresentationController显示为弹出器。您至少需要指定源视图：

activityViewController.popoverPresentationController.sourceView = YOURDESIREDVIEW;

如果要显示锚定到该视图的任何点的弹出窗口，请使用popoverPresentationController的popoverPresentationController属性指定它。