除非我完全误解了reindex的作用,否则我认为下面的片段应该使用NaN来填充已删除的时间索引:
import pandas as pd
import numpy
dateRange = pd.date_range(start='2014-01-01 1:00:00', periods=8, freq='S')
modifiedRange = dateRange.values
modifiedRange = numpy.delete(modifiedRange, (2), axis=0) # remove third row
ts = pd.Series(range(len(modifiedRange)), index=modifiedRange) # series with a gap
print(ts)
ts.reindex(dateRange) # pad the gap with NaN
print(ts)我得到的输出在这里:
2014-01-01 01:00:00 0
2014-01-01 01:00:01 1
2014-01-01 01:00:03 2
2014-01-01 01:00:04 3
2014-01-01 01:00:05 4
2014-01-01 01:00:06 5
2014-01-01 01:00:07 6
dtype: int64
2014-01-01 01:00:00 0
2014-01-01 01:00:01 1
2014-01-01 01:00:03 2
2014-01-01 01:00:04 3
2014-01-01 01:00:05 4
2014-01-01 01:00:06 5
2014-01-01 01:00:07 6
dtype: int64两个指纹是一样的..。但是,我希望第二个包含填充的NaN值:
2014-01-01 01:00:00 0
2014-01-01 01:00:01 1
2014-01-01 01:00:02 NaN
2014-01-01 01:00:03 2
2014-01-01 01:00:04 3
2014-01-01 01:00:05 4
2014-01-01 01:00:06 5
2014-01-01 01:00:07 6
dtype: int64发布于 2014-08-04 21:34:17
reindex不在现场.这么做,你就会得到你想要的。
ts = ts.reindex(dateRange)
print(ts)https://stackoverflow.com/questions/25127825
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