我试图从多个表中返回多个计数和平均数,并按性别排序,并得到不正确的数据。我知道以下是不正确的,但我不知道如何解决它。(编辑:按性别分类的问题。见下文。)
以下是查询:
SELECT c.gender AS 'Gender',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
(SELECT COUNT(DISTINCT CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) ) AS 'Open Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Avg Open',
(SELECT COUNT(DISTINCT CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) ) AS 'Click Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Avg Click',
COUNT(DISTINCT ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM ((mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id)
LEFT JOIN mailing_recipient_click mrc ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON c.cons_id = ca.cons_id)
WHERE m.mailing_id = 1
AND gender IS NOT NULL
GROUP BY c.gender;如果字段中的总数是正确的,下面的表将是正确的:
GENDER Mailing Recipient Open Total Avg Open Click Total Avg Click Donations Avg Amt
F 105 2 0.5000 2 0.5000 105 22.5000
M 98 2 0.5000 2 0.5000 98 18.8780编辑:这是我希望达到的目标的一个例子。我确信,上述价值观正在重复。下面的值只是我所期望的例子:
GENDER Mailing Recipient Open Total Avg Open Click Total Avg Click Donations Avg Amt
F 105 8 0.0761 4 0.0380 2 22.5000
M 98 2 0.0204 1 0.0102 1 18.8000编辑:在玩了一会儿之后,我想我已经发现了连接cons表是给我带来问题的回报,但是问题是在使用性别时使用组。为了说明这一点,这个查询(按邮件名称而不是性别分组)工作得很好。
select m.mailing_name AS 'mailing',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
SUM(CASE
when mrc.mailing_recipient_click_type_id = 2 THEN 1
END)
AS 'Open Total',
AVG(CASE
WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1
ELSE 0
END) AS 'Avg Open',
SUM(CASE
WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1
END)
AS 'Click Total',
AVG(CASE
WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1
ELSE 0
END) AS 'Avg Click',
COUNT(ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM
mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id
LEFT JOIN mailing_recipient_click mrc
ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON mr.cons_id = c.cons_id
WHERE m.mailing_id = 1
GROUP BY m.mailing_name;除了第一行和最后一行外,语句是相同的。
发布于 2014-07-31 17:49:54
试试这个:
我不知道你说的Avg Open和Avg Click是什么意思。
SELECT c.gender AS 'Gender',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
SUM(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Open Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Avg Open',
SUM(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Click Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Avg Click',
COUNT(DISTINCT ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id
LEFT JOIN mailing_recipient_click mrc ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON c.cons_id = ca.cons_id
WHERE m.mailing_id = 1
AND gender IS NOT NULL
GROUP BY c.gender;我还认为,mrc.mailing_recipient_click_type_id = 2意味着打开,而mrc.mailing_recipient_click_type_id = 1则意味着单击,对我来说似乎很奇怪。我希望这些数据是排他性的,并存储在两个不同的字段中。
https://stackoverflow.com/questions/25065363
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