使用javascript创建强密码

Question

我下面有一个函数，它创建一个强密码，但是它并不总是添加一个特殊字符和一个数字或大写字母，我如何确保它始终包含这些要求。

密码的要求是它必须

8个或更长的字符，必须有一个特殊的字符，一个大写字母和一个数字包括在其中。

下面显示了我现在拥有的函数

function GenPwd(nMinimumLength,bIsRequired,sNameoftheButton){
            var end=0;
            var index=0;
            var sPassCharactersWithoutSpeacil="!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ";
            var sSpecialCharacters="!#$@*";
            var nSrngLen=sStrgStrAddOnChrs
            var sNumbers="123456789";
            var nMinimunLen=Math.round(nBaseLen/2);
            var PassWordDLength=Math.round((Math.random()*nMinLen)+nMinimumLength+nMinimumLength); //Make sure it is atleadt 8 characters long
            var Password="";
            var PasswordTemporary="";
            for(index = 1; index <= PassWordDLength; index++) {

                nCharacter = Math.round(Math.random()*65);

                 PasswordTemporary = sPassCharactersWithoutSpeacil.charAt(nCharacter);

                while (PWD.indexOf(PasswordTemporary) > -1) {
                    nCharacter = '';
                    nCharacter = Math.round(Math.random()*65);
                    PasswordTemporary = sPassCharactersWithoutSpeacil.charAt(nChar);
                }
                FinalPWD = Password + PasswordTemporary;
            }

这就是我要用的

function GenPwd(nBaseLen,bIsStrong,sBtnName){

        var end=0;
        var index=0;
        var sPassStr="!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ";
        var sStrgStrAddOnChrs="!#$@*";
        var nSrngLen=sStrgStrAddOnChrs
        var sStrgStrAddOnNum="123456789";
        var nMinLen=Math.round(nBaseLen/2);
        var PWDLen=Math.round((Math.random()*nMinLen)+nBaseLen); 
        var PWD="";
        var PWDTmp="";
        //Generate the password
        for(index = 1; index <= PWDLen; index++) {

            nChar = Math.round(Math.random()*65);

            PWDTmp = sPassStr.charAt(nChar);

            while (PWD.indexOf(PWDTmp) > -1) {
                nChar = '';
                nChar = Math.round(Math.random()*65);
                PWDTmp = sPassStr.charAt(nChar);
            }
            PWD = PWD + PWDTmp;
        }

            document.getElementById("pwd").value=PWD;
        EnableBtn(sBtnName);
        return true;
    }

Answer 1

您可以创建一个函数，以确保pwd包含至少一组特定的字符：

function ensurePwdContains(pwd, regexListOfChars, listOfChars) {
    if (!regexListOfChars.test(pwd)) {
        // select random char from listOfChars
        var newChar = listOfChars.charAt(Math.floor(Math.random() * listOfChars.length));

        // insert it into the current pwd in a random location
        // must do +1 to include the location at the end of the string
        var pos = Math.floor(Math.random() * (pwd.length + 1));
        pwd = pwd.slice(0, pos) + newChar + pwd.slice(pos);
    }
    return pwd;
}

此函数将测试密码是否包含传入的regex的至少一个实例。如果不是，它将从listOfChars参数中选择一个随机字符，然后将其插入到随机位置的现有密码中。

然后，在函数的末尾对两种情况分别调用此函数：

FinalPwd = ensurePwdContains(FinalPwd, /[!#\$@*]/, sSpecialCharacters);
FinalPwd = ensurePwdContains(FinalPwd, /[A-Z]/, "ABCDEFGHIJKLMNOPQRSTUWXYZ");

演示：http://jsfiddle.net/jfriend00/ur9FL/

并且，这里是您的整体实现的清理版本。您指的是函数中的许多变量，这些变量要么未在post中定义，要么未在函数中使用，因此我删除了这些变量(因为我不知道它们是什么或它们是如何使用的)。这里有一个更简洁的实现：

function generatePwd(minLen) {
    // create a pwd that is between minLen and ((2 * minLen) + 2) long
    // don't repeat any characters
    // require at least one special char and one capital char
    function rand(max) {
        return Math.floor(Math.random() * max);
    }

    function ensurePwdContains(pwd, regexListOfChars, listOfChars) {
        if (!regexListOfChars.test(pwd)) {
            var newChar = listOfChars.charAt(rand(listOfChars.length));
            var pos = rand(pwd.length + 1);
            pwd = pwd.slice(0, pos) + newChar + pwd.slice(pos);
        }
        return pwd;
    }

    var legalChars = "!#$@*123456789aAbBcCdDeEfFgGhHiIjJkKlLmMnNoOpPqQrRsStTuUvVwWxXyYzZ";
    var specialChars = "!#$@*";
    var specialRegex = /[!#\$@*]/;
    var caps = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
    var capsRegex = /[A-Z]/;
    var nums = "123456789";
    var numRegex = /[1-9]/;

    // make legalChars into an array of chars (easier to deal with)
    legalChars = legalChars.split("");
    var pwd = "", len = minLen + rand(minLen), index;

    // ensure len is not too long
    len = Math.min(legalChars.length, len);

    // now add chars to the pwd string until it is of the desired length
    while (pwd.length < len) {
        index = rand(legalChars.length);
        pwd += legalChars[index];
        // remove the char we just used
        legalChars.splice(index, 1);
    }
    // ensure we have at least one special character and one caps char and one 1-9
    pwd = ensurePwdContains(pwd, specialRegex, specialChars);
    pwd = ensurePwdContains(pwd, capsRegex, caps);
    pwd = ensurePwdContains(pwd, numRegex, nums);
    return pwd;    
}

并且，一个可以生成大量密码的演示程序，这样您就可以看到您得到的变体类型：http://jsfiddle.net/jfriend00/7dReY/。

为了设置密码，我建议您使用第二个函数调用第一个函数来生成密码，并将其放入所选字段中：

function putPasswordInPlace(pwdId, sBtnName) {
     var pwd = generatePwd(8);
     document.getElementById(pwdId).value = pwd;
     EnableButton(sBtnName);
}