我有一个列表,需要由三个方(比如线程)填充,.I正在使用循环屏障来实现这个功能。一切都很好,除了我无法在没有强迫睡眠的情况下使用结果列表。以下是代码:
public class Test{
List<Integer> item = new Vector<Integer>();
public void returnTheList(){
CyclicBarrier cb = new CyclicBarrier(3, new Runnable() {
@Override
public void run() {
System.out.println("All parties are arrived at barrier, lets play -- : " + CyclicBarrierTest.getTheList().size());
//Here I am able to access my resulted list
}
});
CyclicBarrierTest sw1 = new CyclicBarrierTest(cb, new ZetaCode(1500), s);
CyclicBarrierTest sw2 = new CyclicBarrierTest(cb, new ZetaCode(1500),s);
CyclicBarrierTest sw3 = new CyclicBarrierTest(cb, new ZetaCode(1500),s);
Thread th1 = new Thread(sw1, "ZetaCode1");
Thread th2 = new Thread(sw2, "ZetaCode2");
Thread th3 = new Thread(sw3, "ZetaCode3");
th1.start();
th2.start();
th3.start();
}
public static void main(String args[]){
System.out.println("asdfasd");
Test test = new Test();
//ActionClass ac = new ActionClass();
test.returnTheList();
System.out.println("Inside the main method...size of the final list : " +test.item.size() );
}下面是我的CyclicBrrierTest课程:
public class CyclicBarrierTest implements Runnable{
private CyclicBarrier barrier;
private Object obj;
static volatile String s = "";
volatile List<Integer> finalIntList = new Vector<Integer>();
public CyclicBarrierTest(CyclicBarrier barrier, Object obj, String s){
this.barrier = barrier;
this.obj = obj;
}
@Override
public void run(){
try{
System.out.println(Thread.currentThread().getName() + " is waiting on barrier and s is now : " + finalIntList.size());
ZetaCode simple = (ZetaCode)obj;
finalIntList.addAll(simple.getTheItemList());
barrier.await();
System.out.println(Thread.currentThread().getName() + " has crossed the barrier");
}catch(InterruptedException ex){
System.out.println("Error.." + ex.getMessage());
}catch(Exception e){
System.out.println("Error.." + e.getMessage());
}
}
public List<Integer> getTheList(){
return finalIntList;
}因此,如果我在没有任何延迟的情况下运行这段代码,主方法中的print语句给我列表的长度为零,但是在适当的睡眠之后,它会给出预期的输出,我希望在不提供任何delay.Any帮助的情况下实现同样的结果,我们将不胜感激。提前谢谢。
发布于 2014-07-17 07:54:19
在这里,您似乎希望使用CountDownLatch,而不是CyclicBarrier。CyclicBarrier完全按照预期工作--您的主要方法并不是等待它被所有三个线程绊倒。当您给它一个睡眠语句时,其他3个线程恰好在main再次醒来之前就完成了。
当您需要CyclicBarrier工作人员在继续工作之前都到达相同的“检查点”时,N是非常有用的,而工作人员本身就是唯一关心的人。但是,这里有一个N + 1用户,main线程,它想知道它们什么时候都完成了,而CyclicBarrier不支持这个用例。
请注意,当然,您也可以同时使用它们。
发布于 2019-08-16 06:29:34
在这段代码中,我们有4个任务。Task1、Task2、生成int值的Task3和Task4将添加所有int值。在调用Task4 ()之后,等待Task1、Task2、Task3来生成它们所调用的values.When,而Task4将添加它们的值并打印o/p和call reset()方法,这样屏障就会重置。重置后,此过程将再次继续。
package practice;
import java.util.concurrent.BrokenBarrierException;
import java.util.concurrent.CyclicBarrier;
public class CyclicbarrierExample {
public static void main(String[] args) {
CyclicBarrier c = new CyclicBarrier(4);
Task1 t1 = new Task1(c);
Task2 t2 = new Task2(c);
Task3 t3 = new Task3(c);
Task4 t4 = new Task4(c);
t1.start();
t2.start();
t3.start();
t4.start();
}
}
class Task1 extends Thread {
CyclicBarrier c;
static int t1 ;
public Task1(CyclicBarrier c) {
this.c = c;
}
@Override
public void run() {
while (true) {
t1 = t1 + 1;
try {
c.await();
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
} catch (BrokenBarrierException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
}
class Task2 extends Thread {
CyclicBarrier c;
static int t2;
public Task2(CyclicBarrier c) {
this.c = c;
}
@Override
public void run() {
while (true) {
t2 = t2 + 1;
try {
c.await();
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
} catch (BrokenBarrierException e) {
e.printStackTrace();
}
}
}
}
class Task3 extends Thread {
CyclicBarrier c;
static int t3;
public Task3(CyclicBarrier c) {
this.c = c;
}
@Override
public void run() {
while (true) {
t3 = t3 + 1;
try {
c.await();
Thread.sleep(1000);
} catch (InterruptedException e) {
e.printStackTrace();
} catch (BrokenBarrierException e) {
e.printStackTrace();
}
}
}
}
class Task4 extends Thread {
CyclicBarrier c;
static int t4;
static int count=0;
public Task4(CyclicBarrier c) {
this.c = c;
}
@Override
public void run() {
while (count<10) {
try {
c.await();
} catch (InterruptedException e) {
e.printStackTrace();
} catch (BrokenBarrierException e) {
e.printStackTrace();
}
t4 = Task1.t1 + Task2.t2 + Task3.t3;
System.out.println(t4);
try {
c.reset();
} catch (Exception e) {
System.out.println("yo");
}
count++;
}
}
}https://stackoverflow.com/questions/24797578
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