通过UIMenuItem of UIMenuController传递值

Question

在UITableViewCell中，我使用以下方法在长按下显示菜单。

我需要传递一个值按下删除菜单项-(无效)numberDelete方法。

-(void)handleLongPress:(UILongPressGestureRecognizer *)gestureRecognizer {

    if(gestureRecognizer.state == UIGestureRecognizerStateBegan) {

        CGPoint p = [gestureRecognizer locationInView: self.pullTableView];
        NSIndexPath *indexPath = [self.pullTableView indexPathForRowAtPoint:p];
        if(indexPath != nil) {

            [self becomeFirstResponder];
            NSInteger *row = indexPath.row;

            //need to pass this row value through @selector(numberDelete:)

            UIMenuItem *delete = [[UIMenuItem alloc] initWithTitle:@"Delete" action:@selector(numberDelete:)];

            UIMenuController *menu = [UIMenuController sharedMenuController];
            [menu setMenuItems:[NSArray arrayWithObjects:delete, nil]];
            [menu setTargetRect:[self.pullTableView rectForRowAtIndexPath:indexPath] inView:self.pullTableView];
            [menu setMenuVisible:YES animated:YES];
        }

    }

}

-(void)numberDelete:(id)sender {
   //receive value of row here
}

-(BOOL)canBecomeFirstResponder {
    return YES;
}

-(BOOL)canPerformAction:(SEL)action withSender:(id)sender {
    if (action == @selector(customDelete:) ){
        return YES;
    }
    return NO;
}

Answer 1

如此简单，只需创建一个类型为UIMenuItem的类，在其中添加属性，并使用您的UIMenuItem class而不是实际的UIMenuItem。看看怎么做。

创建一个类，比如MyMenuItem of type UIMenuItem。

MyMenuItem.h

#import <UIKit/UIKit.h>

@interface MyMenuItem : UIMenuItem
@property(nonatomic, strong)NSIndexPath *indexPath;
@end

MyMenuItem.m

#import "MyMenuItem.h"

@implementation MyMenuItem

@end

然后

{
    MyMenuItem *deleteMenuItem = [[MyMenuItem alloc] initWithTitle:@"Delete" action:@selector(numberDelete:)];
    deleteMenuItem.indexPath=indexPath;//Assign to property

    UIMenuController *menu = [UIMenuController sharedMenuController];
    [menu setMenuItems:[NSArray arrayWithObjects:deleteMenuItem, nil]];
    [menu setTargetRect:[self.pullTableView rectForRowAtIndexPath:indexPath] inView:self.pullTableView];
    [menu setMenuVisible:YES animated:YES];
}



-(void)numberDelete:(id)sender {
   //receive value of row here. The sender in iOS 7 is an instance of UIMenuController.
   UIMenuController *targetSender = (UIMenuController *)sender ;
   MyMenuItem *menuItem=(MyMenuItem *)[targetSender.menuItems firstObject]; 

   NSLog(@"%d",menuItem.indexPath.row); 
}

希望能帮上忙。

干杯。

Answer 2

Swift 4中接受答案的修正版本

MenuItemWithIndexPath.swift：

class MenuItemWithIndexPath: UIMenuItem {
    var indexPath: IndexPath?

    init(title: String, action: Selector, indexPath: IndexPath) {
        super.init(title: title, action: action)
        self.indexPath = indexPath
    }
}

用法：

let menu = UIMenuController.shared
menu.menuItems = [MenuItemWithIndexPath(title: "Delete", action: #selector(numberDelete(sender:)), indexPath: indexPath)]
menu.setTargetRect(tableView.rectForRow(at: indexPath), in: tableView)
menu.setMenuVisible(true, animated: true)


@objc func numberDelete(sender:UIMenuController) {
    if let menuItem = sender.menuItems?.first as? MenuItemWithIndexPath,
        let indexPath = menuItem.indexPath {
        print("delete at indexPath: \(indexPath)")
    }
}

Answer 3

我用这种方式解决了这类问题：

 self.becomeFirstResponder()
 let deleteMenuItem = UIMenuItem(title: ConstantString.title_delete, action: #selector(deleteItem(_:)))
 let menuController = UIMenuController.shared
 menuController.menuItems = [deleteMenuItem]
 menuController.accessibilityHint = String(indexPath.row)
 menuController.setMenuVisible(true, animated: true)


@objc func deleteItem(_ sender: UIMenuController) {
     print("delete menu item tapped! index path? \(sender.accessibilityHint)")
}

我用了“飞毛腿4”，希望能帮上忙。