有没有人有任何经验,在移动一个简单的4引线,双极步进电机与庞蒂克大易卡和quick420板?我只是想简单地尝试包括控制步进电机的Arduino例子,并将它们移植过来,以便它们能够在Pontech环境下正常工作。我试图转换的代码如下:
/*
Stepper Motor Control - one revolution
This program drives a unipolar or bipolar stepper motor.
The motor is attached to digital pins 8 - 11 of the Arduino.
The motor should revolve one revolution in one direction, then
one revolution in the other direction.
Created 11 Mar. 2007
Modified 30 Nov. 2009
by Tom Igoe
*/
#include <Stepper.h>
const int stepsPerRevolution = 200; // change this to fit the number of steps per revolution
// for your motor
// initialize the stepper library on pins 8 through 11:
Stepper myStepper(stepsPerRevolution, 8,9,10,11);
void setup() {
// set the speed at 60 rpm:
myStepper.setSpeed(60);
// initialize the serial port:
Serial.begin(9600);
}
void loop() {
// step one revolution in one direction:
Serial.println("clockwise");
myStepper.step(stepsPerRevolution);
delay(500);
// step one revolution in the other direction:
Serial.println("counterclockwise");
myStepper.step(-stepsPerRevolution);
delay(500);
}我的问题是,我不知道如何正确转换的部分,它定义的引脚8,9,10和11的那些有电机引线。我知道它在.cpp文件中这样做。我在下面包括了Stepper.h和Stepper.cpp
/*
Stepper.h - - Stepper library for Wiring/Arduino - Version 0.4
Original library (0.1) by Tom Igoe.
Two-wire modifications (0.2) by Sebastian Gassner
Combination version (0.3) by Tom Igoe and David Mellis
Bug fix for four-wire (0.4) by Tom Igoe, bug fix from Noah Shibley
Drives a unipolar or bipolar stepper motor using 2 wires or 4 wires
When wiring multiple stepper motors to a microcontroller,
you quickly run out of output pins, with each motor requiring 4 connections.
By making use of the fact that at any time two of the four motor
coils are the inverse of the other two, the number of
control connections can be reduced from 4 to 2.
A slightly modified circuit around a Darlington transistor array or an L293 H-bridge
connects to only 2 microcontroler pins, inverts the signals received,
and delivers the 4 (2 plus 2 inverted ones) output signals required
for driving a stepper motor.
The sequence of control signals for 4 control wires is as follows:
Step C0 C1 C2 C3
1 1 0 1 0
2 0 1 1 0
3 0 1 0 1
4 1 0 0 1
The sequence of controls signals for 2 control wires is as follows
(columns C1 and C2 from above):
Step C0 C1
1 0 1
2 1 1
3 1 0
4 0 0
The circuits can be found at
http://www.arduino.cc/en/Tutorial/Stepper
*/
// ensure this library description is only included once
#ifndef Stepper_h
#define Stepper_h
// library interface description
class Stepper {
public:
// constructors:
Stepper(int number_of_steps, int motor_pin_1, int motor_pin_2);
Stepper(int number_of_steps, int motor_pin_1, int motor_pin_2, int motor_pin_3, int motor_pin_4);
// speed setter method:
void setSpeed(long whatSpeed);
// mover method:
void step(int number_of_steps);
int version(void);
private:
void stepMotor(int this_step);
int direction; // Direction of rotation
int speed; // Speed in RPMs
unsigned long step_delay; // delay between steps, in ms, based on speed
int number_of_steps; // total number of steps this motor can take
int pin_count; // whether you're driving the motor with 2 or 4 pins
int step_number; // which step the motor is on
// motor pin numbers:
int motor_pin_1;
int motor_pin_2;
int motor_pin_3;
int motor_pin_4;
long last_step_time; // time stamp in ms of when the last step was taken
};
#endif现在是Stepper.cpp
/*
Stepper.cpp - - Stepper library for Wiring/Arduino - Version 0.4
Original library (0.1) by Tom Igoe.
Two-wire modifications (0.2) by Sebastian Gassner
Combination version (0.3) by Tom Igoe and David Mellis
Bug fix for four-wire (0.4) by Tom Igoe, bug fix from Noah Shibley
Drives a unipolar or bipolar stepper motor using 2 wires or 4 wires
When wiring multiple stepper motors to a microcontroller,
you quickly run out of output pins, with each motor requiring 4 connections.
By making use of the fact that at any time two of the four motor
coils are the inverse of the other two, the number of
control connections can be reduced from 4 to 2.
A slightly modified circuit around a Darlington transistor array or an L293 H-bridge
connects to only 2 microcontroler pins, inverts the signals received,
and delivers the 4 (2 plus 2 inverted ones) output signals required
for driving a stepper motor.
The sequence of control signals for 4 control wires is as follows:
Step C0 C1 C2 C3
1 1 0 1 0
2 0 1 1 0
3 0 1 0 1
4 1 0 0 1
The sequence of controls signals for 2 control wires is as follows
(columns C1 and C2 from above):
Step C0 C1
1 0 1
2 1 1
3 1 0
4 0 0
The circuits can be found at
http://www.arduino.cc/en/Tutorial/Stepper
*/
#include "WProgram.h"
#include "Stepper.h"
/*
* two-wire constructor.
* Sets which wires should control the motor.
*/
Stepper::Stepper(int number_of_steps, int motor_pin_1, int motor_pin_2)
{
this->step_number = 0; // which step the motor is on
this->speed = 0; // the motor speed, in revolutions per minute
this->direction = 0; // motor direction
this->last_step_time = 0; // time stamp in ms of the last step taken
this->number_of_steps = number_of_steps; // total number of steps for this motor
// Arduino pins for the motor control connection:
this->motor_pin_1 = motor_pin_1;
this->motor_pin_2 = motor_pin_2;
// setup the pins on the microcontroller:
pinMode(this->motor_pin_1, OUTPUT);
pinMode(this->motor_pin_2, OUTPUT);
// When there are only 2 pins, set the other two to 0:
this->motor_pin_3 = 0;
this->motor_pin_4 = 0;
// pin_count is used by the stepMotor() method:
this->pin_count = 2;
}
/*
* constructor for four-pin version
* Sets which wires should control the motor.
*/
Stepper::Stepper(int number_of_steps, int motor_pin_1, int motor_pin_2, int motor_pin_3, int motor_pin_4)
{
this->step_number = 0; // which step the motor is on
this->speed = 0; // the motor speed, in revolutions per minute
this->direction = 0; // motor direction
this->last_step_time = 0; // time stamp in ms of the last step taken
this->number_of_steps = number_of_steps; // total number of steps for this motor
// Arduino pins for the motor control connection:
this->motor_pin_1 = motor_pin_1;
this->motor_pin_2 = motor_pin_2;
this->motor_pin_3 = motor_pin_3;
this->motor_pin_4 = motor_pin_4;
// setup the pins on the microcontroller:
pinMode(this->motor_pin_1, OUTPUT);
pinMode(this->motor_pin_2, OUTPUT);
pinMode(this->motor_pin_3, OUTPUT);
pinMode(this->motor_pin_4, OUTPUT);
// pin_count is used by the stepMotor() method:
this->pin_count = 4;
}
/*
Sets the speed in revs per minute
*/
void Stepper::setSpeed(long whatSpeed)
{
this->step_delay = 60L * 1000L / this->number_of_steps / whatSpeed;
}
/*
Moves the motor steps_to_move steps. If the number is negative,
the motor moves in the reverse direction.
*/
void Stepper::step(int steps_to_move)
{
int steps_left = abs(steps_to_move); // how many steps to take
// determine direction based on whether steps_to_mode is + or -:
if (steps_to_move > 0) {this->direction = 1;}
if (steps_to_move < 0) {this->direction = 0;}
// decrement the number of steps, moving one step each time:
while(steps_left > 0) {
// move only if the appropriate delay has passed:
if (millis() - this->last_step_time >= this->step_delay) {
// get the timeStamp of when you stepped:
this->last_step_time = millis();
// increment or decrement the step number,
// depending on direction:
if (this->direction == 1) {
this->step_number++;
if (this->step_number == this->number_of_steps) {
this->step_number = 0;
}
}
else {
if (this->step_number == 0) {
this->step_number = this->number_of_steps;
}
this->step_number--;
}
// decrement the steps left:
steps_left--;
// step the motor to step number 0, 1, 2, or 3:
stepMotor(this->step_number % 4);
}
}
}
/*
* Moves the motor forward or backwards.
*/
void Stepper::stepMotor(int thisStep)
{
if (this->pin_count == 2) {
switch (thisStep) {
case 0: /* 01 */
digitalWrite(motor_pin_1, LOW);
digitalWrite(motor_pin_2, HIGH);
break;
case 1: /* 11 */
digitalWrite(motor_pin_1, HIGH);
digitalWrite(motor_pin_2, HIGH);
break;
case 2: /* 10 */
digitalWrite(motor_pin_1, HIGH);
digitalWrite(motor_pin_2, LOW);
break;
case 3: /* 00 */
digitalWrite(motor_pin_1, LOW);
digitalWrite(motor_pin_2, LOW);
break;
}
}
if (this->pin_count == 4) {
switch (thisStep) {
case 0: // 1010
digitalWrite(motor_pin_1, HIGH);
digitalWrite(motor_pin_2, LOW);
digitalWrite(motor_pin_3, HIGH);
digitalWrite(motor_pin_4, LOW);
break;
case 1: // 0110
digitalWrite(motor_pin_1, LOW);
digitalWrite(motor_pin_2, HIGH);
digitalWrite(motor_pin_3, HIGH);
digitalWrite(motor_pin_4, LOW);
break;
case 2: //0101
digitalWrite(motor_pin_1, LOW);
digitalWrite(motor_pin_2, HIGH);
digitalWrite(motor_pin_3, LOW);
digitalWrite(motor_pin_4, HIGH);
break;
case 3: //1001
digitalWrite(motor_pin_1, HIGH);
digitalWrite(motor_pin_2, LOW);
digitalWrite(motor_pin_3, LOW);
digitalWrite(motor_pin_4, HIGH);
break;
}
}
}
/*
version() returns the version of the library:
*/
int Stepper::version(void)
{
return 4;
}发布于 2014-07-20 20:13:13
看起来Arduino库的目的是直接给步进器的绕组注入能量。BigEasy有一个快板步进驱动芯片,采取步骤和方向输入。它们是苹果和橘子。您可以将AccelStep库与BigEasy一起使用,并且它已经被移植到chipKIT。
发布于 2014-07-15 17:45:14
我猜你指的是quick240板,因为我找不到quick420。如果我理解你的问题,你想把步进函数引脚映射到MPIDE使用的数组值标识的引脚上吗?
引脚8实际上是B端口,pin 0 (PB0)是C1IO3 (pin RB0 on the示意图),Pin 9是B端口,Pin 1是C0IO3 (pin RB1) Pin 10是PB2转换为C1IO1 (pin RB2) Pin 11是PB3翻译成C1IO0 (pin RB3)
C标识卡槽,而IO号是插槽的引脚。数组使用卡片插槽和引脚作为索引,这样你就可以在大部分的路上找到它。
为此,使用Arduino pinout获取引脚的端口号,然后使用quick240原理图将端口和引脚转换为卡槽和IO号。如果你愿意的话,你可以向另一个方向翻译。
https://stackoverflow.com/questions/24709206
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