在运行一个雄辩的联接查询时,我得到了一些意想不到的结果。我通过使用完全相同的查询得到两个不同的结果。一次运行DB::raw(),第二次运行雄辩。
在雄辩的查询中,匹配
where squad_user.leave_time >= seasons.start_time
将不包括在结果集中。匹配的用户。
or squad_user.leave is null
不过,将包括在内。
这是两个查询结果的唯一不同之处。原始查询实际上生成所需的结果集。
真正让我困惑的是,如果我检查查询日志,无论是Laravel的还是MySQL的,我在运行原始和雄辩的查询时都会得到完全相同的查询。
原始查询(运行雄辩查询时从查询日志获得的实际查询)
return \DB::select(\DB::raw('
select users.*
from users
inner join squad_user on users.id = squad_user.user_id
inner join seasons on squad_user.squad_id = seasons.squad_id
where squad_user.join_time <= seasons.end_time
and (squad_user.leave_time >= seasons.start_time or squad_user.leave_time is null)
and seasons.id = :seasonId
'),
['seasonId' => 3]
);雄辩的质疑
return User::join('squad_user', 'users.id', '=', 'squad_user.user_id')
->join('seasons', 'squad_user.squad_id', '=', 'seasons.squad_id')
->where('squad_user.join_time', '<=', 'seasons.end_time')
->where(function ($query)
{
$query->where('squad_user.leave_time', '>=', 'seasons.start_time')
->orWhereNull('squad_user.leave_time');
})
->where('seasons.id', 3)
->get(['users.*']);Laravel雄辩的查询日志
select `users`.*
from `users`
inner join `squad_user` on `users`.`id` = `squad_user`.`user_id`
inner join `seasons` on `squad_user`.`squad_id` = `seasons`.`squad_id`
where `squad_user`.`join_time` <= seasons.end_time
and (`squad_user`.`leave_time` >= seasons.start_time or `squad_user`.`leave_time` is null)
and `seasons`.`id` = 3
{"bindings":["seasons.end_time","seasons.start_time",3],"time":0.38,"name":"mysql"}MySQL在雄辩的查询上的general_log
select `users`.*
from `users`
inner join `squad_user` on `users`.`id` = `squad_user`.`user_id`
inner join `seasons` on `squad_user`.`squad_id` = `seasons`.`squad_id`
where `squad_user`.`join_time` <= ?
and (`squad_user`.`leave_time` >= ? or `squad_user`.`leave_time` is null)
and `seasons`.`id` = ? MySQL在原始查询上的general_log
select users.*
from users
inner join squad_user on users.id = squad_user.user_id
inner join seasons on squad_user.squad_id = seasons.squad_id
where squad_user.join_time <= seasons.end_time
and (squad_user.leave_time >= seasons.start_time or squad_user.leave_time is null)
and seasons.id = ?我很感激这里的任何指点,因为我非常迷茫。
发布于 2014-07-08 21:55:31
where绑定第三个param,并通常将其作为字符串处理,除非您通过使用raw语句告诉它不要这样做。DB::raw或whereRaw将为您工作:
return User::join('squad_user', 'users.id', '=', 'squad_user.user_id')
->join('seasons', 'squad_user.squad_id', '=', 'seasons.squad_id')
->where('squad_user.join_time', '<=', DB::raw('seasons.end_time'))
->where(function ($query)
{
$query->where('squad_user.leave_time', '>=', DB::raw('seasons.start_time'))
->orWhereNull('squad_user.leave_time');
})
->where('seasons.id', 3)
->get(['users.*']);发布于 2020-08-04 09:12:14
由于LaravelVerian5.2,您还可以使用whereColumn来验证两个列是否相等(或者向该方法传递一个比较运算符):
->whereColumn('squad_user.join_time', '<=', 'seasons.end_time')https://stackoverflow.com/questions/24641068
复制相似问题