用Python对itertools.permutations进程进行细分

Question

是否有任何方法细分占用大量内存的进程(在本例中为itertools.permutations)，以提高效率和不耗尽内存？

Answer 1

你已经用itertools.permutations把自己逼到了绝境。你真的需要检查所有可能的排列吗？您的字典非常小，所以只需遍历字典本身并验证每个单词：

import itertools
from collections import Counter

with open('/usr/share/dict/american-english', 'r') as handle:
    dictionary = frozenset(line.strip() for line in handle)

def existing_words(letters, length):
    letters_counter = Counter(letters)
    letters_set = frozenset(letters)

    for word in dictionary:
        if len(word) != length:
            continue

        if set(word) <= letters_set and Counter(word) <= letters_counter:
            yield word

if __name__ == '__main__':
    for word in existing_words('abcdefghijklmnopqrst', 5):
        print word