CGIHTTPServer和Python
CGIHTTPServer和Python
提问于 2014-06-24 15:40:20
我目前正在编写一个python程序，它使用sys.stdout.print()打印HTML页面，脚本名为hellocgi.py，它位于Mac上桌面上的cgi-bin目录中。
以下是代码：
import sys
sys.stdout.write("Content-type: text/html \r\n\r\n")
sys.stdout.write("<!doctype html><html><head><title>Hello World</title></head>")
sys.stdout.write("<body><h2>Hello CGI</h2></body></html>")然后，我在cgi-bin目录中运行命令python -m CGIHTTPServer，当我要访问url localhost:8000/hellocgi.py时，我得到的是火狐内部的源代码。
如果我试图在cgi-bin之外运行python -m CGIHTTPServer，则在url localhost:8000/cgi-bin/上会出现错误。
误差响应 错误代码403 消息: CGI脚本不是普通文件(‘/cgi/’)。 错误代码解释: 403 =请求被禁止-授权不会有帮助。
在网址localhost:8000/cgi-bin/hellocgi.py火狐提示我下载源代码。
Python版本:2.7.5MacOSX: 10.9
python -m CGIHTTPServer日志：
Serving HTTP on 0.0.0.0 port 8000 ...
127.0.0.1 - - [24/Jun/2014 18:34:49] "GET / HTTP/1.1" 200 -
127.0.0.1 - - [24/Jun/2014 18:34:51] code 403, message CGI script is not a plain file ('/cgi-bin/')
127.0.0.1 - - [24/Jun/2014 18:34:51] "GET /cgi-bin/ HTTP/1.1" 403 -
127.0.0.1 - - [24/Jun/2014 18:36:01] "GET /cgi-bin/hellocgi.py HTTP/1.1" 200 -
Traceback (most recent call last):
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 253, in run_cgi
os.execve(scriptfile, args, env)
OSError: [Errno 13] Permission denied
127.0.0.1 - - [24/Jun/2014 18:36:01] CGI script exit status 0x7f00
^CTraceback (most recent call last):
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/runpy.py", line 162, in _run_module_as_main
"__main__", fname, loader, pkg_name)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/runpy.py", line 72, in _run_code
exec code in run_globals
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 378, in <module>
test()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/CGIHTTPServer.py", line 374, in test
SimpleHTTPServer.test(HandlerClass, ServerClass)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SimpleHTTPServer.py", line 216, in test
BaseHTTPServer.test(HandlerClass, ServerClass)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/BaseHTTPServer.py", line 599, in test
httpd.serve_forever()
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 236, in serve_forever
poll_interval)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/SocketServer.py", line 155, in _eintr_retry
return func(*args)有什么帮助吗？
回答 1
Stack Overflow用户
发布于 2015-02-11 19:51:53
#!/usr/bin/python
import sys
sys.stdout.write("Content-type: text/html \r\n\r\n")
sys.stdout.write("<!doctype html><html><head><title>Hello CGI</title></head>")
sys.stdout.write("<body><h2>Hello CGI</h2></body></html>")并添加到文件chmod +x querys.py中。
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原文链接：
https://stackoverflow.com/questions/24390888
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