在第一个主题帮助我正确地将数据发送给使用UDP协议的人之后,我在接收这些数据时遇到了问题。这个问题很奇怪,只在我第一次启动发送数据的函数时才会发生。第一次,服务器只接收第一帧。但是之后,如果我使用这个函数,一切都很好。
下面是通过UDP协议发送数据的代码(我的数据是一个结构):
void MyUDP::sendUDP()
{
//Structure to send
typedef struct MyStructTag
{
int test1;
bool test2;
char test3;
} MyStruct;
MyStruct envoie;
envoie.test1 = 1;
envoie.test2 = true;
envoie.test3 = 97;
// Sends the datagram datagram
// to the host address and at port.
// qint64 QUdpSocket::writeDatagram(const QByteArray & datagram,
// const QHostAddress & host, quint16 port)
QByteArray buf;
QDataStream s(&buf, QIODevice::WriteOnly);
// The encoding is big endian by default, on all systems. You
// can change it if you wish.
if (false) s.setByteOrder(QDataStream::LittleEndian);
s << (qint32)envoie.test1 << (quint8)envoie.test2 << (qint8)envoie.test3;
//I'm sending 5 frames
socket->writeDatagram(buf, QHostAddress("10.100.14.79"), 4000);
socket->writeDatagram(buf, QHostAddress("10.100.14.79"), 4000);
socket->writeDatagram(buf, QHostAddress("10.100.14.79"), 4000);
socket->writeDatagram(buf, QHostAddress("10.100.14.79"), 4000);
socket->writeDatagram(buf, QHostAddress("10.100.14.79"), 4000);
}下面是允许我接收这些数据的函数:
void MyUDP::readyRead()
{
QHostAddress sender;
quint16 senderPort;
// qint64 QUdpSocket::readDatagram(char * data, qint64 maxSize,
// QHostAddress * address = 0, quint16 * port = 0)
// Receives a datagram no larger than maxSize bytes and stores it in data.
// The sender's host address and port is stored in *address and *port
// (unless the pointers are 0).
typedef struct MyStructTag
{
int test1;
bool test2;
char test3;
} MyStruct;
MyStruct recois;
socket->readDatagram((char*)&recois, sizeof (recois), &sender, &senderPort);
qDebug() << "Message from: " << sender.toString();
qDebug() << "Message port: " << senderPort;
qDebug() << "Message: " << recois.test3;
}为什么我第一次启动sendUDP时只收到一个帧?
发布于 2014-06-12 13:52:24
在你的问题中没有足够的信息来确定,但是当你读一份数据报时,你每读一次只能得到一个数据报。与以流模式读取的TCP不同,UDP是面向消息的.如果您想要读取更多的消息,请在一个循环中多次读取或读取它们。还请注意,你不能依赖保证订单,甚至保证交货.
https://stackoverflow.com/questions/24185337
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