我使用pcreate创建了一个金字塔扇静态应用程序:
pcreate -s starter -s pyramid_fanstatic如果我使用/bin/pserv-扇启动服务器,一切正常。但是,当我使用Apache模块加载应用程序时,链接如下:
<link rel="stylesheet" type="text/css" href="/fanstatic/services/bootstrap/bootstrap.min.css" />返回Apache未找到的404。
这是我的WSGI应用程序:
import os
activate_this = os.path.join('/opt/services/services/bin/activate_this.py')
execfile(activate_this, dict(__file__=activate_this))
os.environ['PYTHON_EGG_CACHE'] = '/opt/services/python-eggs'
from pyramid.paster import get_app, setup_logging
ini_path = '/opt/services/services/development.ini'
setup_logging(ini_path)
application = get_app(ini_path, 'main') 这是我的Apache conf文件:
<VirtualHost *:80>
ServerAdmin a.orth@cgiar.org
ServerName data.ilri.org
# Pass authorization info on (needed for rest api).
WSGIPassAuthorization On
WSGIDaemonProcess services python-path=/opt/services/services display-name=services processes=2 threads=15
WSGIScriptAlias /services /opt/services/services/services/services.wsgi process-group=services application-group=%{GLOBAL}
<Location /services>
WSGIProcessGroup services
</Location>
ErrorLog /var/log/httpd/services.error.log
CustomLog /var/log/httpd/services.custom.log combined
</VirtualHost>在加载应用程序之前,我可以看到/bin/pserve包含我的资源目录:
"""A script aware of static resource"""
import pyramid.scripts.pserve
import pyramid_fanstatic
import os
dirname = os.path.dirname(__file__)
dirname = os.path.join(dirname, 'resources')
pyramid.scripts.pserve.add_file_callback(
pyramid_fanstatic.file_callback(dirname))
pyramid.scripts.pserve.main()但是,即使我在我的init.py中包含了这样的行,Apache也找不到扇静态资源。
我还在ini文件中添加了以下内容:
[filter:fanstatic]
use = egg:fanstatic#fanstatic
[pipeline:main]
pipeline = fanstatic services我还应该检查/做什么?
发布于 2014-06-09 09:37:51
修好了!!
我不得不在app:main中将这一行添加到ini文件中。
fanstatic.publisher_signature = fanstatic
fanstatic.use_application_uri = true根据以下文档:fanstatic
发布于 2014-06-07 03:52:27
您似乎并没有让Apache提供您的静态文件。请参见:
https://stackoverflow.com/questions/24084446
复制相似问题