每10秒发布一条消息

Question

我对mqtt还是新手，而且还发现了这个有趣的协议。我想在python中创建一个客户机，它每10秒发布一条消息。到目前为止，我只成功地发布了一条消息，并将客户端与代理保持连接。

我如何使出版部分成为一个循环？

以下是我的客户：

import mosquitto
mqttc=mosquitto.Mosquitto("ioana")
mqttc.connect("127.0.0.1",1884,60,True)
mqttc.publish("test","Hello")
mqttc.subscribe("test/", 2)

while mqttc.loop() == 0:
pass

谢谢。

Answer 1

你可以在通话之间睡觉：

import mosquitto
import time # import time module
mqttc=mosquitto.Mosquitto("ioana")
mqttc.connect("127.0.0.1",8000,60,True)
mqttc.subscribe("test/", 2)
while mqttc.loop() == 0:
    mqttc.publish("test","Hello")
    time.sleep(10)# sleep for 10 seconds before next call

Answer 2

我建议：

import paho.mqtt.client as mqtt # mosquitto.py is deprecated
import time

mqttc = mqtt.Client("ioana")
mqttc.connect("127.0.0.1", 1883, 60)
#mqttc.subscribe("test/", 2) # <- pointless unless you include a subscribe callback
mqttc.loop_start()
while True:
    mqttc.publish("test","Hello")
    time.sleep(10)# sleep for 10 seconds before next call