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两个字段的计数MySQL组
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Stack Overflow用户
提问于 2014-05-23 22:32:34
回答 2查看 42关注 0票数 0
代码语言:javascript
复制
mysql> SELECT date_format(FROM_UNIXTIME(timestamp), '%M') AS month,   
       YEAR(FROM_UNIXTIME(timestamp)) as year, left(content_value, 12) AS status, 
       count(*) AS count FROM gg_groom_content 
       WHERE content_value LIKE '%created ofi%' OR 
       content_value LIKE '%ofi rejected%' 
       GROUP BY MONTH(from_unixtime(timestamp)), YEAR(from_unixtime(timestamp));

Result:
+-----------+------+--------------+-------+
| month     | year | status       | count |
+-----------+------+--------------+-------+
| January   | 2014 | OFI Rejected |   861 |
| February  | 2014 | Created OFI: |   777 |
| March     | 2014 | Created OFI: |   537 |
| April     | 2014 | OFI Rejected |   285 |
| May       | 2014 | OFI Rejected |   198 |
| September | 2011 | (06:32:40 PM |     1 |
| November  | 2013 | Created OFI: |    86 |
| December  | 2013 | Created OFI: |   561 |
+-----------+------+--------------+-------+
8 rows in set (0.91 sec)

然而,我试着每个月都有自己的状态:

例如:

五月应该有一个总数量的OFI拒绝和总数量的创建OFI。我怎样才能做到这一点?

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回答 2

Stack Overflow用户

回答已采纳

发布于 2014-05-23 22:50:25

也许有更好的解决方案,但您可以尝试使用UNION ALL进行两个单独的查询,如下所示

代码语言:javascript
复制
SELECT date_format(FROM_UNIXTIME(timestamp), '%M') AS month,   
YEAR(FROM_UNIXTIME(timestamp)) as year, left(content_value, 12) AS status, 
count(*) AS count FROM gg_groom_content 
WHERE content_value LIKE '%created ofi%'
GROUP BY MONTH(from_unixtime(timestamp)), YEAR(from_unixtime(timestamp));

UNION ALL

SELECT date_format(FROM_UNIXTIME(timestamp), '%M') AS month,   
YEAR(FROM_UNIXTIME(timestamp)) as year, left(content_value, 12) AS status, 
count(*) AS count FROM gg_groom_content 
WHERE content_value LIKE '%ofi rejected%' 
GROUP BY MONTH(from_unixtime(timestamp)), YEAR(from_unixtime(timestamp));
票数 1
EN

Stack Overflow用户

发布于 2014-05-23 22:53:12

我认为您要寻找的是有条件的聚合:

代码语言:javascript
复制
SELECT date_format(FROM_UNIXTIME(timestamp), '%M') AS month,   
       YEAR(FROM_UNIXTIME(timestamp)) as year, left(content_value, 12) AS status, 
       sum(content_value LIKE '%created ofi%') as CreatedOFI,
       sum(content_value LIKE '%ofi rejected%') as RejectedOFI
FROM gg_groom_content 
WHERE content_value LIKE '%created ofi%' OR 
      content_value LIKE '%ofi rejected%' 
GROUP BY MONTH(from_unixtime(timestamp)), YEAR(from_unixtime(timestamp))
ORDER BY MIN(timestamp);
票数 0
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/23839225

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