JSON数据获取公共数据列表: Jquery或Javascript

Question

我想知道我的JSON数据中有多少网站

[{"name":"Lenovo Thinkpad 41A4298","website":"google"},
{"name":"Lenovo Thinkpad 41A2222","website":"google"},
{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
{"name":"Lenovo Thinkpad 41A424448","website":"google"},
{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}]

我想输出像

var webList="google,yahoo,ebay,rediff";

或

webList[0]="google";
webList[1]="yahoo";
webList[2]="ebay";
webList[3]="rediff";

Answer 1

如果需要删除重复的内容，请在使用$.inArray推送前检查该数组

var data=[{"name":"Lenovo Thinkpad 41A4298","website":"google"},
{"name":"Lenovo Thinkpad 41A2222","website":"google"},
{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
{"name":"Lenovo Thinkpad 41A424448","website":"google"},
{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}];

var webList = new Array();
$.each(data,function(index,item){
if ($.inArray(item.website, webList)==-1) {
         webList.push(item.website);
    }
});
console.log(webList);

现场演示

Answer 2

这是你想要的：

var data=[{"name":"Lenovo Thinkpad 41A4298","website":"google"},
          {"name":"Lenovo Thinkpad 41A2222","website":"google"},
          {"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
          {"name":"Lenovo Thinkpad 41A424448","website":"google"},
          {"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
          {"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
          {"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
          {"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}];

var webList = new Array();

$.each(data,function(index,item){

    if($.inArray(item.website, webList) == -1)
      webList.push(item.website);

    console.log(webList);

})

您可以通过这种方式访问您想要的项，或者像我在json数组上所做的那样进行迭代：

console.log(webList[0]);

小提琴演示

Answer 3

你可以这样做：

http://jsfiddle.net/DianaNassar/C97DJ/1/

var data = [{"name":"Lenovo Thinkpad 41A4298","website":"google"},
{"name":"Lenovo Thinkpad 41A2222","website":"google"},
{"name":"Lenovo Thinkpad 41Awww33","website":"yahoo"},
{"name":"Lenovo Thinkpad 41A424448","website":"google"},
{"name":"Lenovo Thinkpad 41A429rr8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ff8","website":"ebay"},
{"name":"Lenovo Thinkpad 41A429ss8","website":"rediff"},
{"name":"Lenovo Thinkpad 41A429sg8","website":"yahoo"}];

var uniqueNames = [];
for(i = 0; i< data.length; i++){    
    if(uniqueNames.indexOf(data[i].website) === -1){
        uniqueNames.push(data[i].website);        
    }        
}

for(i = 0; i< uniqueNames.length; i++){    
    alert(uniqueNames[i]);      
}