复制/克隆Vector.<MovieClip>

Question

如何复制向量的内容？

private var slotMC:MovieClip;
    private var slotV1:Vector.<MovieClip> = new Vector.<MovieClip>();
    private var slotV2:Vector.<MovieClip>;
    private var slotV3:Vector.<MovieClip>;

    public function InputSlot():void {
        registerClassAlias("MovieClip", MovieClip);
        for (var i:int = 1; i < typeAmount + 1; i++) {                      
            SlotClass = Main.queue.getLoader('main_uiMC').getClass('slot0' + i) as Class;
            slotMC = new SlotClass();
            slotMC.name = "slot" + i;

            //push to vector before randomly add to stage
            slotV1.push(slotMC);
        }

        slotV2 = clone(slotV1);
        trace('slotv2', slotV2);
    }

    private function clone(source:Vector.<MovieClip>):Vector.<MovieClip> {  
        var myBA:ByteArray = new ByteArray();
        myBA.writeObject(source);
        myBA.position = 0;

        return myBA.readObject() as Vector.<MovieClip>;
    }

它返回slotV2的null。或者在这种情况下，多维向量会是更好的方式吗？我不知道我还会在未来的MC中添加什么信息。

Answer 1

除非对象的类实现DisplayObject，否则不能深入克隆任何类型的IExternalizable向量。这是因为深入克隆一个DisplayObject需要克隆它的所有引用，包括整个子列表和阶段，您不能再做另一个阶段了。因此，最好通过在循环中创建更多的SlotClass实例并将它们填充到相应的向量中来创建“深度克隆”。

for (var i:int = 1; i < typeAmount + 1; i++) {                      
        SlotClass = Main.queue.getLoader('main_uiMC').getClass('slot0' + i) as Class;
        slotMC = new SlotClass();
        // slotMC.name = "slot" + i; 
        // drop name setting, you'd better use position in vector to refer to the clip

        //push to vector before randomly add to stage
        slotV1.push(slotMC);
        slotMC = new SlotClass();
        slotV2.push(slotMC);
        slotMC = new SlotClass();
        slotV3.push(slotMC);
    }

不要忘记在运行循环之前初始化向量。

另外一点是，考虑到为什么需要这几个向量，使用多维向量可能更好。