Python find_overlapping tuple？

Question

在python画布中，“find_overlapping”函数返回什么？

from tkinter import *
a = Tk()
table = Canvas(a, width=500, height=300, bg='white')
table.pack()

my_oval = table.create_oval(40, 40, 80, 80)

c_object = table.find_overlapping(30, 30, 70, 70)
print(c_object)

a.mainloop()
>>> (1, )

元组返回到控制台。我想要的是为my_oval分配一个ID，而不是返回一个元组，我希望返回ID。

my_oval.[some_kind_of_id] = 'myID'
c_object = table.find_overlapping(30, 30, 70, 70)
print(c_object)
>>> (1, )
# I want 'myID' to be printed

*注意:由于我的some_kind_of_id分配，上面的代码将返回一个语法错误。我想要的三点：

1)给形状分配某种ID

2)某一点的find_overlapping

3)如果形状与点重叠，则返回形状的ID

编辑:为了弄清楚我想要什么，我正在用平纹机做一个游戏，如果我的方格碰到一堵墙，它就会停下来，但是如果它碰到一个硬币，它就会继续前进。因此，如果由正方形返回的id (内置函数'find_overlapping')属于墙，则广场将停止。

Answer 1

我对画布不太熟悉，但看起来find_overlapping正在为您创建的每个椭圆返回一个ID，从1开始递增。实际上，如果您打印了oval对象：

print(my_oval)

它返回1，如果你有第二个，并打印它，它将是2。

因此，这只是一个跟踪每个椭圆的对象ID的问题。考虑一个字典来保存所有的id；当您创建一个椭圆时，您会给它一个id并将它插入到字典中。然后，创建一个函数(overlaps())，返回与重叠值匹配的所有键的列表。

看看这个工作示例，如果有什么不合理的地方，请告诉我：

from tkinter import *

def overlaps((x1, y1, x2, y2)):
    '''returns overlapping object ids in ovals dict'''
    oval_list = [] # make a list to hold overlap objects
    c_object = table.find_overlapping(x1, y1, x2, y2)
    for k,v in ovals.items():  # iterate over ovals dict
        if v in c_object:      # if the value of a key is in the overlap tuple
            oval_list.append(k)# add the key to the list
    return oval_list

a = Tk()

# make a dictionary to hold object ids
ovals = {}

table = Canvas(a, width=500, height=300, bg='white')
table.pack()

# create oval_a and assign a name for it as a key and
# a reference to it as a value in the ovals dict.
# the key can be whatever you want to call it
# create the other ovals as well, adding each to the dict
# after it's made
oval_a = table.create_oval(40, 40, 80, 80)
ovals['oval_a'] = oval_a

oval_b = table.create_oval(60, 60, 120, 120)
ovals['oval_b'] = oval_b

oval_c = table.create_oval(120, 120, 140, 140)
ovals['oval_c'] = oval_c

# draw a rectangle
rectangle = table.create_rectangle(30, 30, 70, 70)

# print the return value of the overlaps function
# using the coords of the rectangle as a bounding box
print(overlaps(table.coords(rectangle)))

a.mainloop()