问题解编组POJO

Question

有一个webservice，它有我需要检索的3个java对象。这些是物体

 @XmlRootElement(name="licenseFile")
    @XmlAccessorType(XmlAccessType.FIELD)
    public class XmlLicenseFile implements Cloneable
    {
        //URI Info
        public static final String URI_PATH = "licenseFiles";
        @XmlAttribute
        private String url;

        //Base License Info
        private String licenseFileId;
        private String licenseStatus; 
        private String licenseFileType; 
        private String licenseFileVersion;

        //Request Info
        private String requestSource;
        private String locale;
        private Boolean overrideErrors;
        private String internallyRequestingUserId;
        private String requestorUserProfileId;
        private String externalIpAddress;
        private Boolean internalUseOnly;

        //Contract Info
        private String serviceId; //Used to be called contractNumber
        private String contractAdminName;
        private String contractAdminEmail;
        private String organizationName;
        private String contractStartDate;
        private String contractEndDate;
        private Boolean overdraftAllowed;
        private String vlaType;
        private Integer vlaLogAutoSendFrequency;

        //Server Info
        @XmlElementWrapper(name="licenseServers")
        @XmlElement(name="licenseServer")
        private List<XmlLicenseServer> licenseServers;

        //License Package Info
        @XmlElementWrapper(name="licensePackages")
        @XmlElement(name="licensePackage")
        private List<XmlLicensePackage> licensePackages;

        //Error Info
        private String errorType; 
        private Integer errorCode;
        private String errorDescription;

        //Database Info
        private String creationDate;
        private String lastUpdateDate;

        //License Content
        private String licenseFileName;
        private String licenseFileContent;

        public String getOrganizationName() {
        return organizationName;
        }
        public void setOrganizationName(String organizationName) {
        this.organizationName = organizationName;
        }
        // ALL OF THE OTHER SETTERS AND GETTERS GO HERE
 }   

@XmlRootElement(name="licensePackage")
@XmlAccessorType(XmlAccessType.FIELD)
public class XmlLicensePackage 
{
    //URI Info
    public static final String URI_PATH = "licensePackages";
    @XmlAttribute
    private String url;

    //Base Package Info
    private String licensePackageId;
    private String licenseFileId;
    private String packageStatus; 


    private String partNumber;

    //Package Info
    private String packageName;
    private String packageVersion; //Calculated
    private String operatingSystem; //Can be calculated or passed in

    //Generation Info
    private String serialNumber;
    private Integer seatCount;
    private String packageExpireDate;

    //Client/Concurrency Info
    private String concurrencyType; 
    private String clientType; 

    //Reconciliation Info
    private String productReconciliationId;

    //Error Info
    private String errorType; 
    private Integer errorCode;
    private String errorDescription;

    //Database Info
    private String creationDate;
    private String lastUpdateDate;
        //ALL THE GETTERS AND SETTERS
}

@XmlRootElement(name="licenseServer")
@XmlAccessorType(XmlAccessType.FIELD)
public class XmlLicenseServer
{
    private String serverName;
    private String computerId;
    //ALL SETTERS AND GETTERS HERE
}

我的问题是如何解决这个问题。这是GET密码。客户端变量是一个泽西客户端。

public static XmlLicenseFile getLicenseFile(String key){
        XmlLicenseFile returnedFile = null;
        URI uri = constructURIByFileId(key); //THIS CREATES THE URI, AND I'VE CONFIRMED IT'S CORRECT
        try{
            WebResource webResource = client.resource(uri.toString());
            returnedFile = webResource.accept(MediaType.APPLICATION_XML).get(XmlLicenseFile.class);
            if(returnedFile == null){
                throw new ProviderException(ResponseErrorType.NOT_FOUND, "The license file doesn't exists", "", "");
            } //TODO Fill error cases
        }catch(Exception e){
            logger.error(e);
            throw new ProviderException(ResponseErrorType.INTERNAL_SERVICE_ERROR, "Internal Server Error", "", "");
        }
        return returnedFile;
    }

每次我尝试运行代码时，它都会在webResource.accept(MediaType.APPLICATION_XML).accept(XmlLicenseFile.class)部分失败。它在ClientException中失败。你知道为什么解构失败了吗？

-编辑--这是正在构建的URI localhost/myWS/1.0/licenseFiles/EBB080CCFB02309AE0440021287E6A9E

如果在浏览器中单击该URL，它将返回有效的licenseFile。

Answer 1

因此，问题是URI没有"http://“部分”。一旦我加进去，一切都成功了！