我希望能够访问span类中的文本,同时也能够获得span类之外的信息。例如:
以下是XML文档信息的示例:
<item><title>Operations Applications - MDI Diagnostics</title><link>http://confidential-link.com</link>
<description><![CDATA[<div style="margin-top:5px"><link rel="stylesheet" type="text/css" href="confidential" />
<span class="srch-Icon"><a href="confidential" title="Operations Applications - MDI Diagnostics">
<img src="confidential" alt="Web Page" border="0" /></a></span>
<span class="psrch-Description"> THE INFORMATION I WANT</span>
<p class="srch-Metadata"><span class="srch-URL">
<a href="confidential" title="Operations Applications - MDI Diagnostics">confidential link</a>
-
66KB
</span></p></div>]]></description>
<author>Bob Smith
</author><pubDate>Mon, 10 Mar 2014 18:53:49 GMT</pubDate><search:dotfileextension>.ASPX</search:dotfileextension><search:size>68076</search:size>
<search:hithighlightedsummary> SIMILAR TO THE INFORMATION I WANT, COULD BE OPTION 2 </search:hithighlightedsummary>
</item>我现在拥有的是:
var feeds = from feed in xdoc.Descendants("item")
select new RSSS
{
Site = "TOPS",
URL = url,
Title = feed.Element("title").Value,
Link = feed.Element("link").Value,
Description = feed.Element("description").Value
};它按预期返回“描述”:
<div style="margin-top:5px"><link rel="stylesheet" type="text/css" href="confidential" />
<span class="srch-Icon"><a href="confidential" title="Operations Applications - MDI Diagnostics">
<img src="confidential" alt="Web Page" border="0" /></a></span>
<span class="psrch-Description"> THE INFORMATION I WANT</span>
<p class="srch-Metadata"><span class="srch-URL">
<a href="confidential" title="Operations Applications - MDI Diagnostics">confidential link</a>
-
66KB
</span></p></div>那么,我如何具体地访问"span class = psrch-Description“之间的信息,同时仍然能够访问链接和标题之类的信息?
**因为我不是在找像
var feeds = from feed in xDoc.Descendants("Show") where (string)feed.Attribute("Code") == "456" select new { EventDate = feed.Attribute("Date").Value };
这不允许我获得其他信息。
发布于 2014-04-25 15:40:22
如果<Description>包含符合XML的HTML,则可以将其加载到另一个XDocument变量:
XDocument description = XDocument.Parse(feed.Element("description").Value);然后,您可以使用另一个LINQ查询来获取您感兴趣的<Description>值的任何部分。
否则,您将需要另一种类型,例如可以处理HtmlAgilityPack的HtmlDocument。
https://stackoverflow.com/questions/23297095
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