基于cin.fail的CIN验证

Question

我正在开发一个小程序，它使用std::cin一个接一个地要求4个整数。我使用一个函数来请求整数，并传入允许作为参数的最大值。若要检查该值是否为整数，请使用std::cin.fail。调用函数的代码如下所示。

    cout << "Specify source number (1 - 1024)\n";
    source = validate(1024);
    cout << "Specify destination number (1 - 1024)\n";         // For all except data, the value is equal to the value returned by the validate function
    destination = validate(1024);                              // The maximum possible value is passed in as an argument in each of the cases.
    cout << "Specify type number (1 - 10)\n";                  // User  is prompted to enter the desired values.
    type = validate(10);
    cout << "Source port number (1 - 1024)\n";
    port = validate(1024);

验证函数代码如下所示。

int validate(int max) {

int value;                                  // Initialise variable to hold the value.

for (;;) {                                  // Loop forever until correct input is entered.
    cin >> value;

    if (cin.fail()) {                // If cin fails to receive a value matching the declared data type.
        cout << "Characters are not permitted.\n";          // Notify the user of error.
        cin.clear();                    // Clear the error flag within cin.
        cin.ignore(10000,'\n');         // Ignore the newline character in the buffer to prevent an infinite loop.
        }
    else if (value > max || value == 0) {
        cout << "The value you have entered is not valid, please enter a number between 1 and " << max << "\n";
        cin.clear();                    // Clear the error flag within cin.
        cin.ignore(10000, '\n');        // Ignore the newline character in the buffer to prevent an infinite loop.
    }
    else
        break;
    }
return value;                           // Return the validated value.
}

如果用户只输入一个整数，或者只输入一个字母，它就会正常工作。我遇到的问题是，如果用户输入了34d或22p。我得到了一个错误：characters are not permitted，但是它退出了函数并转移到下一个请求。

试着重新安排，所有的事情似乎都解决不了。任何帮助都非常感谢

Answer 1

您想要做的是对行的其余部分进行ignore，即使您成功了：

int validate(int max) {

int value;                                  // Initialise variable to hold the value.

for (;;) {                                  // Loop forever until correct input is entered.
    cin >> value;

    if (cin.fail()) {                // If cin fails to receive a value matching the declared data type.
        cout << "Characters are not permitted.\n";          // Notify the user of error.
        cin.clear();                    // Clear the error flag within cin.
        cin.ignore(10000,'\n');         // Ignore the newline character in the buffer to prevent an infinite loop.
        }
    else if (value > max || value == 0) {
        cout << "The value you have entered is not valid, please enter a number between 1 and " << max << "\n";
        cin.clear();                    // Clear the error flag within cin.
        cin.ignore(10000, '\n');        // Ignore the newline character in the buffer to prevent an infinite loop.
    }
    else {
        cin.ignore(10000, '\n');        // Ignore the newline character in            
        break;
    }
}
return value;                           // Return the validated value.
}

如果你认为这是重复的，你可以这样做：

struct ignore_till_eol {
  ignore_till_eol(std::istream& cin): input(cin) {}
  ~ignore_till_eol() { input.clear(); input.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); }
  std::istream& input;
};

int validate(int max_value) {
  for(;;) {
    ignore_till_eol ignore(cin);
    int v;
    if( cin >> v && 0 < v && v <= max_value ) return v;
    if( cin )
        cout << "Value is invalid, must be between 1 and " << max_value << "\n";
    else
        cout << "Invalid characters in input\n";
  }
}

或

int validate(int max_value) {
  for(;;) {
    ignore_till_eol ignore(cin);
    int v;
    if( !(cin >> v) )
        cout << "Invalid characters in input\n";
    else if( 0 < v && v <= max_value )
        return v;
    else
        cout << "Value is invalid, must be between 1 and " << max_value << "\n";
  }
}