我有一个非常慢的查询,因为使用ORDER。现在我明白了它为什么慢,但我不知道我如何使它更快。
这张桌子有1300万份记录。(速度慢的原因)
表30行13,591,548数据1.3 GiB索引265.2 MiB总计1.5 GiB开销96 B
$sql3 = mysql_query("SELECT * FROM config LIMIT 1");
$row3 = mysql_fetch_assoc($sql3);
$log=$row3['con_log'];
$sql2 = mysql_query("SELECT sl_start,sl_id FROM scan_list2 WHERE sl_scanned='0' ORDER BY sl_id LIMIT 40");
while($row2 = mysql_fetch_assoc($sql2)){
echo "crk|".$row2['sl_start']."|".$log."-";
$sl_id = $row2['sl_id'];
mysql_query("UPDATE scan_list2 SET sl_scanned='1' WHERE sl_id='$sl_id'");对这个问题有什么更好的解决办法吗?
发布于 2014-04-17 03:14:05
首先检查您的表索引。
在php中,您不需要对每40行执行一次更新,然后运行update然后运行select,然后执行一个循环来显示来自select的行的信息,例如:
mysql_query("UPDATE scan_list2 SET sl_scanned = '1' WHERE sl_scanned = '0' ORDER BY sl_id LIMIT 40");
$sql3 = mysql_query("SELECT * FROM config LIMIT 1");
$row3 = mysql_fetch_assoc($sql3);
$log=$row3['con_log'];
$sql2 = mysql_query("SELECT sl_start,sl_id FROM scan_list2 WHERE sl_scanned = '1' ORDER BY sl_id DESC LIMIT 40");
while($row2 = mysql_fetch_assoc($sql2)){
echo "crk|".$row2['sl_start']."|".$log."-";
}发布于 2014-04-17 05:27:50
相反,通过添加联接,尝试更改更新查询以更新一次更新中的所有记录。
UPDATE scan_list2
INNER JOIN
(
SELECT sl_start,sl_id
FROM scan_list2
WHERE sl_scanned='0'
ORDER BY sl_id
LIMIT 40
) b ON scan_list2.sl_id = b.sl_id
SET sl_scanned='1' https://stackoverflow.com/questions/23123542
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