用断线和解析隔开句子。

Question

考虑到我已经用一个分行符分隔了标记语句，并且我有两个列表示标记的实际和预测标记。我想遍历每一个标记，找出错误的预测，例如实际的标记不等于预测的标记。

#word actual predicted

James PERSON PERSON
Washington PERSON LOCATION     
went O O
home O LOCATION

He O O
took O O
Elsie PERSON PERSON
along O O

>James Washington went home: Incorrect
>He took Elsie along: Correct

Answer 1

除了我的previous answer之外，我还在这里使用all()和列表理解：

from itertools import groupby

d = {True: 'Correct', False: 'Incorrect'}
with open('text1.txt') as f:
    for k, g in groupby(f, key=str.isspace):
        if not k:
            # Split each line in the current group at whitespaces
            data = [line.split() for line in g] 
            # If for each line the second column is equal to third then `all()` will
            # return True.
            predicts_matched = all(line[1] == line[2] for line in data)
            print ('{}: {}'.format(' '.join(x[0] for x in data), d[predicts_matched]))

输出：

James Washington went home: Incorrect
He took Elsie along: Correct

Answer 2

Python字符串具有强大的解析功能，您可以在这里使用。我使用Python3.3完成了这个操作，但是它也应该适用于任何其他版本。

thistext = '''James PERSON PERSON
Washington PERSON LOCATION     
went O O
home O LOCATION

He O O
took O O
Elsie PERSON PERSON
along O O
'''

def check_text(text):
    lines = text.split('\n')
    correct = [True] #a bool wrapped in a list,we can modify it from a nested function
    words = []

    def print_result():
        if words:
            print( ' '.join(words), ": ", "Correct" if correct[0] else "Incorrect" )
        #words.clear()
        del words[:]        
        correct[0] = True

    for line in lines:
        if line.strip():  # check if the line is empty
            word, a, b = line.split()
            if a != b:
                correct[0] = False
            words.append(word)
        else:
            print_result();

    print_result()

check_text(thistext)