Medoo，简短的ajax语法

Question

我对Medoo框架有问题，它们都在localhost (php > 5.4+)上工作得很好，但是在我的服务器上安装了5.3+，您能帮助我如何将这些代码转换成旧的数组版本，并在PHP5.3上执行代码吗？平台。

$database = new medoo array(
    // required
    'database_type' => 'mysql',
    'database_name' => 'mytable',
    'server' => 'localhost',
    'username' => 'root',
    'password' => '',

 // optional
    'port' => 3306,
    'charset' => 'utf8',
        'option' => [
        PDO::ATTR_CASE => PDO::CASE_NATURAL
    ]
);


$database->insert("table", [
    "project_name" => "Some text",
    "project_owner" => "Some Text",
    "project_time" => "10/10/2014",
    "project_target" => "- Target one, - Target two, - Target three",
    "project_details" => "This is my project."
]);

Answer 1

<?php
require  'medoo.php';

$database = new medoo(array(
    'database_type' => 'mysql',
    'database_name' => 'test',
    'server' => 'localhost',
    'username' => 'testu',
    'password' => 'asdf'


));

$database->insert("table", array(
    "project_name" => "x",
    "project_owner" => "x",
    "project_time" => "x",
    "project_target" => "x",
    "project_details" => "x"
))
?>

Answer 2

用数组调用替换括号。所有括号都是数组的简短形式。

http://www.php.net/manual/en/language.types.array.php