如何正确注释我的类

Question

我正在尝试正确注释我的类，这样我就可以在android框架中使用SimpleXML。我的问题是，我总是：

E/something(25192): Could not read [class at.something.scanner.Issues]; nested exception is org.simpleframework.xml.core.ValueRequiredException: Unable to satisfy @org.simpleframework.xml.ElementList(data=false, empty=true, entry=, inline=true, name=issues, required=true, type=void) on field 'issues' private java.util.List at.something.scanner.Issues.issues for class at.something.scanner.Issues at line 1

和

E/something(25192): Caused by: org.simpleframework.xml.core.ValueRequiredException: Unable to satisfy @org.simpleframework.xml.ElementList(data=false, empty=true, entry=, inline=true, name=issues, required=true, type=void) on field 'issues' private java.util.List at.something.scanner.Issues.issues for class at.something.scanner.Issues at line 1

我知道我可以通过使用@ElementList(required=false)来摆脱required=false，但是它不能解决我的问题，因为我最终得到了一个空列表。

请求使用spring：

RestTemplate restTemplate = new RestTemplate();
restTemplate.getMessageConverters().add(new StringHttpMessageConverter());              
Serializer serializer = new Persister(new Format("<?xml version=\"1.0\" encoding= \"UTF-8\" ?>"));
restTemplate.getMessageConverters().add(new SimpleXmlHttpMessageConverter(serializer));
ResponseEntity<Issues> response = restTemplate.exchange(url, HttpMethod.GET, new HttpEntity<Object>(requestHeaders), Issues.class);
Issues tickets = response.getBody();

Issues.java：

@Root
public class Issues{

@ElementList(name="issues", inline=true)
    private List<Issue> issues;

    public void setIssues(List<Issue> results) {
        this.issues = results;
    }

    public List<Issue> getIssues() {
        return issues;
    }
}

Issue.java

@Root(name="issue")
public class Issue{

    @Attribute(name="id")
    private String id;
}

来自服务器的XML响应示例：

<issues>
    <issue id="ABC-10">
       <field xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="SingleField" name="Assignee">
          <value>someone</value>
       </field>
    </issue>
    <issue id="ABC-11">
       <field xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="SingleField" name="reporterName">
          <value>someone</value>
       </field>
    </issue>
</issues>

我希望有人能给我一个如何解决我的问题的提示。

Answer 1

使用

@ElementList(name="issues", inline=true, entry="Issue")

我也遇到了同样的问题，这对我来说很有好处。在Stackoverflow网站上找到了这个答案。

编辑：

我已经用简单的XML尝试了您的示例，对于类问题，您已经使用了

@Element(name="field")
private Field field;

失踪了。

public class Field {

     @Element(name = "value", required = true)
     private String value;

     @Attribute(name = "name", required = false)
     private String name;

}

我还用了

public static void main(String args[]) throws Exception {
    Serializer serializer = new Persister(new Format("<?xml version=\"1.0\" encoding= \"UTF-8\" ?>"));
    File source = new File("sample.xml");
    Issues i = serializer.read(Issues.class, source);

}

我没有任何错误。使用来自xml的数据正确地加载了对象。