标题已经-令人困惑的版本-。在当地工作，而不是生活

Question

我知道在php代码之前不应该有空格。但是，我的代码在活动服务器上给出了以下错误，但是在测试服务器上，不是：

警告:无法修改已由/home/mydomain/public_html/parts/includes/dbinfo.inc.php:5)发送的标头信息(输出从第55行的/home/mydomain/public_html/parts/update_part.php中的/home/mydomain/public_html/parts/update_part.php开始)

我已经尝试过删除functions.inc.php，但仍然存在同样的问题。下面是所涉及的两段代码: a) dbinfo.inc.php

    <?php
$username="myusername";
$password="mypassword";
$database="mydatabase";
?> 

( b) update_part.php

<?php

include("./includes/dbinfo.inc.php");
include("./includes/functions.inc.php");

mysql_connect("localhost","$username","$password") or die("Error: ".mysqlerror());
mysql_select_db("$database"); 

//get the variables we transmitted from the form
        $part_id            = $_POST['part_id'];
        $part_manufacturer      = $_POST['part_manufacturer'];
        $part_descr             = $_POST['part_descr'];
        $part_price         = $_POST['part_price'];
        $part_code          = $_POST['part_code'];
        $part_status            = $_POST['part_status'];
        $part_image             = $_POST['part_image'];
        $part_cat           = $_POST['part_cat'];
        $ave_mth_usage          = $_POST['ave_mth_usage'];
        $reorder_level          = $_POST['reorder_level'];
        $reorder_qty            = $_POST['reorder_qty'];
        $other_item_details             = $_POST['other_item_details'];
        $part_stock_taking_date         = $_POST['part_stock_taking_date'];
        $part_qty_in_stock      = $_POST['part_qty_in_stock'];


        $part_manufacturer      = mysql_real_escape_string($part_manufacturer);
        $part_descr             = mysql_real_escape_string($part_descr);
        $part_code          = mysql_real_escape_string($part_code);
        $part_status            = mysql_real_escape_string($part_status);
        $part_cat           = mysql_real_escape_string($part_cat);
        $other_item_details             = mysql_real_escape_string($other_item_details);


//replace TestTable with the name of your table
$sql = 
    "UPDATE part SET 
        part_manufacturer       = '$part_manufacturer',
        part_descr          = '$part_descr',
        part_price          = '$part_price',
        part_code           = '$part_code',
        part_status             = '$part_status',
        part_image          = '$part_image',
        part_cat            = '$part_cat',
        ave_mth_usage           = '$ave_mth_usage',
        reorder_level           = '$reorder_level',
        reorder_qty             = '$reorder_qty',
        other_item_details      = '$other_item_details',
        part_stock_taking_date          = '$part_stock_taking_date',
        part_qty_in_stock       = '$part_qty_in_stock'


    WHERE part_id = $part_id";
//mysql_query($sql) or die ("Error: ".mysql_error());
do_query($sql,__LINE__);
header("Location: ./view_parts.php");
?>

第55行的违规代码是b的最后一行之前的一行。

header("Location: ./view_parts.php");

有什么想法吗？

Answer 1

您应该从php脚本和打开标记之前的所有空格中删除php结束标记，并在包含的php脚本中再次删除这一切。

Answer 2

检查文件编码-使用UTF-8 没有BOM.可以使用输出缓冲。

Answer 3

听起来您正在向页面输出错误或警告。检查页面的来源。

要使“header”命令工作，必须没有先前的输出。

如果使用ob_clean()，输出缓冲可能会有所帮助。您还可以关闭显示php.ini文件中的错误。