我的应用程序是通过串口(usb串行)与嵌入式系统通信。
我正在使用QT4.8和QtSerialPort从gitorious (https://qt.gitorious.org/qt/qtserialport/)开发,我还在使用Windows7和QT5.2.1的VM中进行测试。
它在Linux下运行得很好,但是我得到了相同消息的双读,三读四读。我可以验证这些消息只发送一次,通过puTTY进行通信。
所以问题是,这是一个问题的QtSerialPort,虚拟机(虽然它工作在putty?),串行驱动程序.等。
这是众所周知的问题吗?(不过,我什么也找不到)有什么办法找出真相吗?
我就是这样读到的:
编辑: moar代码:
ModuleCommunicator::ModuleCommunicator(const QString &device, SBStateModel &state_model)
: upstate(UpdateDone), model(state_model)
{
port = new QSerialPort(device);
if (!port->open(QIODevice::ReadWrite /*| QIODevice::Truncate*/)) {
qDebug() << "Failed to open - Portname: " << port->portName() << endl;
qDebug() << "Error: " << port->errorString() << endl;
return;
}
port->setBaudRate(QSerialPort::Baud115200, QSerialPort::AllDirections);
port->setParity(QSerialPort::NoParity);
port->setStopBits(QSerialPort::OneStop);
port->setDataBits(QSerialPort::Data8);
port->setFlowControl(QSerialPort::NoFlowControl);
msgBuffer = new QStringList();
log_init = false;
connect(port, SIGNAL(readyRead()), this, SLOT(onReadyRead()));
connect(port, SIGNAL(error(QSerialPort::SerialPortError)), this, SLOT(onError(QSerialPort::SerialPortError)));
connect(port, SIGNAL(aboutToClose()), this, SLOT(devClosing()));
/* Timer for log level */
conTimer = new QTimer(this);
connect(conTimer, SIGNAL(timeout()), this, SLOT(timerFired()));
}
ModuleCommunicator::~ModuleCommunicator()
{
if (port->isOpen())
port->close();
delete msgBuffer;
delete port;
}
...
void ModuleCommunicator::onReadyRead()
{
if (port->bytesAvailable()) {
QString msg = QString(port->readAll());
msgBuffer->append(msg);
if (msg.endsWith("\n")) {
msg = msgBuffer->join("").trimmed();
msgBuffer->clear();
msgBuffer->append(msg.split("\r\n"));
} else {
return;
}
for (int i = 0; i < msgBuffer->size(); i++) {
msg = msgBuffer->at(i);
qDebug() << "MSG: " << msg << endl;
if (isResponse(msg)) {
handleMsg(msg);
}
}
msgBuffer->clear();
}
}编辑:有意思。取消注释“刷新()”会使事情正常工作。通过刷新,我看到了成倍的消息。但在接收端?是否有可能,由于“刷新()”而多次发送消息?
void ModuleCommunicator::handleMsg(const QString &msg)
{
// Parse msg
QSharedPointer<USBResponse> resp = QSharedPointer<USBResponse>(parse_message(msg));
if (!resp->is_valid()) {
// LOG
return; // Invalid response
}
// omitted
/* Find completion handler for response
Match to first command in Queue with same command & address,
or same command and wildcard adress */
// Omitted
// Sending next msg in queue if there is one
if (!sendQueue.isEmpty()) {
QueuedCommand qc = sendQueue.takeFirst();
QString nxtcmd = qc.cmdstr;
completionHandlerQueue.append(qc.ch);
qDebug() << "handleMsg: Sending next msg: " << qc.cmdstr;
if (port->write(nxtcmd.toLatin1()) == -1) {
qDebug() << "handleMsg: write failed!";
}
// !!! Removing the following line makes things work?!
port->flush();
}
return;}
发布于 2014-04-11 13:17:17
这些问题是由调用“刷新”方法引起的。在写入串口后删除刷新调用解决了这个问题。
似乎“刷新”方法存在已知的问题(尽管文档中的提示很好,直到它被修复为止)。下面是我发现的bug报告:
https://bugreports.qt-project.org/browse/QTBUG-36726
引用:
是的,刷新()方法还存在bug。请不要使用冲水器()。
https://stackoverflow.com/questions/22836468
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