icu：：日历：：createInstance()泄漏内存

Question

下面是一个泄漏的测试程序(在Ubuntu10.04，ICU 4.2上)：

#include <unicode/uversion.h>
#include <unicode/calendar.h>

int main()
{
  TimeZone* tz = TimeZone::createTimeZone("Asia/Pyongyang");

  UErrorCode status = U_ZERO_ERROR;
  Calendar* cal = Calendar::createInstance(tz, status); // adopts tz

  delete cal;
}

valgrind --leak-check=full说：

==22978== 304 bytes in 1 blocks are possibly lost in loss record 20 of 22
==22978==    at 0x4C28F86: malloc (vg_replace_malloc.c:291)
==22978==    by 0x526B34D: icu_4_2::UnicodeString::allocate(int) (in /usr/lib/libicuuc.so.42.1)
==22978==    by 0x526B993: icu_4_2::UnicodeString::cloneArrayIfNeeded(int, int, signed char, int**, signed char) (in /usr/lib/libicuuc.so.42.1)
==22978==    by 0x526D97A: icu_4_2::UnicodeString::doReplace(int, int, unsigned short const*, int, int) (in /usr/lib/libicuuc.so.42.1)
==22978==    by 0x4EF0E90: icu_4_2::TimeZone::initDefault() (in /usr/lib/libicui18n.so.42.1)
==22978==    by 0x4EF10A4: icu_4_2::TimeZone::createDefault() (in /usr/lib/libicui18n.so.42.1)
==22978==    by 0x4EEE750: icu_4_2::GregorianCalendar::GregorianCalendar(icu_4_2::Locale const&, UErrorCode&) (in /usr/lib/libicui18n.so.42.1)
==22978==    by 0x4EEB493: ??? (in /usr/lib/libicui18n.so.42.1)
==22978==    by 0x4EEBA01: icu_4_2::Calendar::createInstance(icu_4_2::TimeZone*, icu_4_2::Locale const&, UErrorCode&) (in /usr/lib/libicui18n.so.42.1)
==22978==    by 0x400A42: icu_4_2::Calendar::createInstance(icu_4_2::TimeZone*, UErrorCode&) (in /home/jzwinck/test/a.out)
==22978==    by 0x4009C5: main

我的问题是，我是不正确地使用ICU，还是有什么解决办法可以应用于释放ICU似乎正在创建的默认时区对象？我不能轻易地改变我正在使用的操作系统和ICU的版本。

Answer 1

你需要打电话给u_cleanup()来清理重症监护病房。通常这并不重要，所以不是自动完成的。如果您使用--enable-auto-cleanup构建ICU，它将尝试在库卸载时在某些平台上进行清理。见用户指南。