当Angular.js $resouce不是对象时，它不会JSONify postData吗？

Question

lubanlockServices.factory('UserConfig', ['$resource',
    function($resource){
        return $resource('user/config/:item', {item: '@item'});
    }
]);

lubanlockControllers.controller('NavCtrl', ['$scope', 'UserConfig',
    function($scope, UserConfig){
        $scope.minimized = UserConfig.get({item: 'nav_minimized'});

        $scope.$watch('minimized', function(value){
            console.log(value);
        });

        $scope.toggleMinimize = function(){
            $scope.minimized = !$scope.minimized;
            UserConfig.save({item: 'nav_minimized'}, $scope.minimized);
        }
    }
]);

问题是，当$scope.minimized为false时，请求将不包含任何post数据，而不是发送JSONified false。这会导致服务器端保存值出现问题。

有解决办法吗？或者我的用法有什么问题吗？

Answer 1

JSON是Javascript对象表示法，您确实应该是POSTing (并检索)一个对象。理想情况下，它看起来应该是：

$scope.config = UserConfig.get({item: 'nav_minimized'}); 
//returns a $resource with data {minimized: false}

$scope.$watch('config.minimized', function(value){
    console.log(value);
});
$scope.toggleMinimize = function(){
    $scope.config.minimized = !$scope.config.minimized;
    $scope.config.$save(); //and then you can do this to save
}