当我执行browser.submit()时,它会显示此错误跟踪(最近一次调用):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_mechanize.py", line 541, in submit
return self.open(self.click(*args, **kwds))
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_mechanize.py", line 528, in click
if not self.viewing_html():
File "/usr/local/lib/python2.7/dist-packages/mechanize-0.2.5-py2.7.egg/mechanize/_mechanize.py", line 443, in viewing_html
raise BrowserStateError("not viewing any document")
mechanize._mechanize.BrowserStateError: not viewing any document我能想到的原因之一是,当我打印browser.form时,它会显示出来
-form-urlencoded
<TextControl(username)>
<PasswordControl(password)>
<HiddenControl(AUTH_STATE=08539313-ae8d-4133-ba21-247a90668ccb) (readonly)>
<SubmitButtonControl(<None>=) (readonly)>>可能是因为它在SubmitButtonControl中没有显示。有人能建议我怎么解决这个问题吗。在html提交按钮的代码是登录是如何解决这一点?
发布于 2014-03-30 09:48:59
问题是您没有得到对browser.submit()的任何响应,因为我认为SubmitButtonControl设置为None。以下是我首先要做的事情:
通过br.select_form(nr=WHATEVER)选择表单,然后使用
for control in br.form.controls:
print control.name以查看它是否会打印出某些标识符。
您的目标是通过这样选择控件来手动分配控件的值.
browser.form['controlname']='login'
browser.urlopen(form.click())如果不能选择控件,那么只需尝试browser.urlopen(form.click())选项,而不是browser.submit()
告诉我是怎么回事。
https://stackoverflow.com/questions/22741740
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