如何有条件地删除元组列表中的元素？

Question

>>> x=[("x1","x2","x3"),("x1","x2"),("x2","x3"),("x3","x4")]
>>> x
[('x1', 'x2', 'x3'), ('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]

我想删除列表中的元组-x，如果len(x[id])==3，len(x[0]==3)，那么它会被删除，[('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]是我想要的，我怎么写代码呢？

[del element if len(element[id]==3) for id,element in enumerate(x)]

invalid syntax.

Answer 1

使用列表理解来筛选元素，将所有内容保持在长度为3的范围内：

x = [el for el in x if len(el) != 3]

演示：

>>> x = [('x1', 'x2', 'x3'), ('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]
>>> [el for el in x if len(el) != 3]
[('x1', 'x2'), ('x2', 'x3'), ('x3', 'x4')]