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使用cuFFT的多个主机线程的奇怪行为
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Stack Overflow用户
提问于 2014-03-19 09:42:21
回答 1查看 689关注 0票数 1

下面的测试程序为每个GPU创建一个主机线程。每个主机线程创建一个cuFFT计划并执行快速傅立叶变换。

大多数情况下,程序运行似乎没有错误。但是,有时它会以各种方式失败(例如,参见下面的输出)。有人知道为什么这个程序有时会失败吗?

我在一台拥有两个英特尔Xeon E5620 CPU、48 GB主机内存和四张特斯拉C2075卡的机器上运行这个程序,这些卡都没有用于显示。操作系统是Linux (Debian7.4),我已经安装了CUDA 5.5版本。NVIDIA驱动程序版本为319.82。作为参考,cuFFT的错误码4和11分别是CUFFT_INVALID_VALUE和CUFFT_INVALID_DEVICE。

更新:我越来越怀疑cuFFT并不像文档所宣称的那样是线程安全的。如果我用互斥保护整个线程(也就是说,一次只能执行一个线程),程序就不会失败。只使用互斥保护cufftPlan1d调用或只保护cufftExecR2C调用将导致程序失败。我是否误解了文件上的内容:

可以从多个独立主机线程调用的线程安全API。

示例1

代码语言:javascript
复制
4 CUDA device(s) found
Device 3 initialized
Device 2 initialized
Device 1 initialized
FFT execution failed for device 1, status = 11
Device 0 initialized
Device 3 deinitialized
Device 2 deinitialized
Device 0 deinitialized

注意,设备1线程没有终止。

示例2

代码语言:javascript
复制
4 CUDA device(s) found
Device 0 initialized
Device 2 initialized
Device 1 initialized
Device 3 initialized
FFT execution failed for device 3, status = 11
Device 2 deinitialized
Device 0 deinitialized
Device 1 deinitialized

示例3

代码语言:javascript
复制
4 CUDA device(s) found
Device 1 initialized
Device 2 initialized
FFT execution failed for device 2, status = 4
Device 1 deinitialized
Device 3 initialized
Device 0 initialized
FFT execution failed for device 0, status = 4
Device 3 deinitialized

例4

代码语言:javascript
复制
4 CUDA device(s) found
Segmentation fault

例5

代码语言:javascript
复制
4 CUDA device(s) found
Device 3 initialized
Device 2 initialized
Device 3 deinitialized
Plan creation failed for device 0, status = 4
^C

在最后一个例子中,程序没有终止。

如果我同时使用for i in {0..9}; do ./pthread_cuda & done运行这个程序的多个副本,它会以新的和有趣的方式失败:

例6

代码语言:javascript
复制
4 CUDA device(s) found
4 CUDA device(s) found
4 CUDA device(s) found
4 CUDA device(s) found
4 CUDA device(s) found
4 CUDA device(s) found
pthread_cuda: pthread_mutex_lock.c:84: __pthread_mutex_lock: Assertion `mutex->__data.__owner == 0' failed.
4 CUDA device(s) found
4 CUDA device(s) found
4 CUDA device(s) found

我没有在程序中使用互斥,那么这个问题是cuFFT库中的一个错误吗?

pthread_cuda代码

代码语言:javascript
复制
#include <cuda_runtime_api.h>
#include <cufft.h>
#include <malloc.h>
#include <math.h>
#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

// The thread configuration structure.
typedef struct
{
    int device;
    pthread_t thread;
    cudaError_t status;
    int np;
}
config_t;

// The size of memory region.
int np = 16384;

// The function executed by each thread assigned with CUDA device.
void *thread_func(void *arg)
{
    // Unpack the config structure.
    config_t *config = (config_t *)arg;

    int device = config->device;

    int fft_in_np = config->np;
    int fft_out_np = config->np / 2 + 1;

    // Set focus on device with the specificed index.
    cudaError_t cuda_status = cudaSetDevice(device);
    if (cuda_status != cudaSuccess) {
        fprintf(stderr, "Cannot set focus to device %d, status = %d\n",
            device, cuda_status);
        config->status = cuda_status;
        pthread_exit(NULL);
    }

    cufftHandle r2c_plan;
    cufftResult cufft_status = cufftPlan1d(&r2c_plan, fft_in_np, CUFFT_R2C, 1);
    if (cufft_status != CUFFT_SUCCESS) {
        fprintf(stderr, "Plan creation failed for device %d, status = %d\n",
            device, cufft_status);
        //config->status = cufft_status;
        pthread_exit(NULL);
    }

    // Create device arrays for input and output data.
    cufftReal *in_dev_data = NULL;
    cufftComplex *out_dev_data = NULL;

    cuda_status = cudaMalloc((void **)&in_dev_data, (fft_in_np + 2) * sizeof(cufftReal));
    if (cuda_status != cudaSuccess) {
        fprintf(stderr, "Cannot allocate CUDA FFT buffer on device %d, status = %d\n",
            device, cuda_status);
        config->status = cuda_status;
        pthread_exit(NULL);
    }

    cuda_status = cudaMalloc((void **)&out_dev_data, fft_out_np * sizeof(cufftComplex));
    if (cuda_status != cudaSuccess) {
        fprintf(stderr, "Cannot allocate CUDA FFT buffer on device %d, status = %d\n",
            device, cuda_status);
        config->status = cuda_status;
        pthread_exit(NULL);
    }

    printf("Device %d initialized\n", device);

    //out_dev_data = (cufftComplex *)in_dev_data;

    cufft_status = cufftExecR2C(r2c_plan, in_dev_data, out_dev_data);
    if (cufft_status != CUFFT_SUCCESS) {
        fprintf(stderr, "FFT execution failed for device %d, status = %d\n",
            device, cufft_status);
        //config->status = cuda_status;
        pthread_exit(NULL);
    }

    cuda_status = cudaDeviceSynchronize();
    if (cuda_status != cudaSuccess) {
        fprintf(stderr, "Failed to synchronize device %d, status = %d\n",
            device, cuda_status);
        config->status = cuda_status;
        pthread_exit(NULL);
    }

    // Dispose device buffers.
    cuda_status = cudaFree(in_dev_data);
if (cuda_status != cudaSuccess) {
        fprintf(stderr, "Cannot release input buffer on device %d, status = %d\n",
            device, cuda_status);
        config->status = cuda_status;
        pthread_exit(NULL);
    }

    cufft_status = cufftDestroy(r2c_plan);
    if (cufft_status != CUFFT_SUCCESS) {
        fprintf(stderr, "Plan destruction failed for device %d, status = %d\n",
            device, cufft_status);
        //config->status = cuda_status;
        pthread_exit(NULL);
    }

    printf("Device %d deinitialized\n", device);

    config->status = 0;
    return NULL;
}

int main(int argc, char* argv[])
{
    int ndevices = 0;
    cudaError_t cuda_status = cudaGetDeviceCount(&ndevices);
    if (cuda_status != cudaSuccess) {
        fprintf(stderr, "Cannot get the cuda device count, status = %d\n",
            cuda_status);
        return cuda_status;
    }

    // Return if no cuda devices present.
    printf("%d CUDA device(s) found\n", ndevices);
    if (!ndevices)
        return 0;

    int dev_num;
    cuda_status = cudaGetDevice(&dev_num);
    if (cuda_status != cudaSuccess) {
        fprintf(stderr, "Cannot get the cuda device number, status = %d\n",
            cuda_status);
        return cuda_status;
    }

    // Create workers configs. Its data will be passed as
    // argument to thread_func.
    config_t* configs = (config_t*)malloc(sizeof(config_t) * ndevices);

    // For each CUDA device found create a separate thread
    // and execute the thread_func.
    for (int i = 0; i < ndevices; i++) {
        config_t *config = configs + i;
        config->device = i;
        config->np = np;
        //config->in_host = in + np * i;

        int status = pthread_create(&config->thread, NULL, thread_func, config);
        if (status) {
            fprintf(stderr, "Cannot create thread for device %d, status = %d\n",
                i, status);
            return status;
        }
    }

    // Wait for device threads completion.
    // Check error status.
    int status = 0;
    for (int i = 0; i < ndevices; i++) {
        pthread_join(configs[i].thread, NULL);
        status += configs[i].status;
    }
    if (status)
        return status;

    free(configs);

    return 0;
}
EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2014-03-21 07:09:18

作为记录,CUDA 6.0RC似乎解决了这个问题。我怀疑这是由cuFFT库中的线程代码中的一个bug引起的,但我不能确定。

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/22501702

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