在Python中,使用这个函数(带am/pm的东部标准时间(EST) )应该以3种时间格式输出它。中央时间(CT)、山区时间(MT)和太平洋时间(PT)均在正确的上午/下午):
def time_in_24h(time,time_day): #time is eastern time
''' (number, str)--> number
This function converts a 12-hour time, represented by am/pm,to its equivalent 24-hour time.
Returns time in the 24-hour format.
'''
cCentral = 'Central Time(CT)' #-1 hour offset
mMountain = 'Mountain Time(MT)'#-2 hours offset
pPacific = 'Pacific Time(PT)'#-3 hours offset
eEst = 'EST is'
if time_day!='pm' and time_day!='am':
print('Input is not in the right format') #this is where input is not in the right format
return 0
else:
print(time, time_day, eEst, time-1, cCentral)
print(time, time_day, eEst, time-2, mMountain)
print(time, time_day, eEst, time-3, pPacific)使用此命令:
time_in_24h(7,'am')我得到了这个输出:
7 am EST is 6 Central Time(CT)
7 am EST is 5 Mountain Time(MT)
7 am EST is 4 Pacific Time(PT)我试图输出正确的3次基于输入的EST,上午/下午到中央时间(CT),山时间(MT)和太平洋时间(PT)都在正确的上午/下午。如何根据偏移量得到正确的am/pm输出?例如,下午2点EST的输入,应该输出:
1 pm EST is 12 pm Central Time(CT)
1 pm EST is 11 am Mountain Time(MT)
1 pm EST is 10 am Pacific Time(PT)正如你所看到的,pm/am的变化是基于补偿的,这是不一致的。根据时间(上午/下午)的不同,处理这一问题的最佳方法是什么?任何在python中构建的东西都可以在没有问题的情况下解决这个问题吗?有办法解决我的困境吗?我付出了我的全部,在这件事上真的坚持了下来。
发布于 2014-03-16 02:01:26
到中环,看看东部时间是下午12点就可以了。如果是,那就调整到上午11点。同样,如果东部时间是午夜,那么调整到晚上11点。这需要一点if,但您可以这样做。
问题是,,它还是错的,。约会时间的数学很难,你已经忘记了DST。
通常,每年一次是东部时间(EST)的凌晨1次,也是中央时间(CDT)的1次。(同样,它也是东部的凌晨3点和中环的1点。)
考虑到您的函数当前的输入量,您不能考虑这一点:您需要知道完整的日期和时间。一旦你这样做了,最简单的办法就是把整个东部(美国/纽约)的日期和时间转换为世界协调时,然后转换成中美洲(美国/芝加哥)、山(美国/丹佛)和太平洋(美国/洛杉矶)。
美国/…位是大多数机器上TZ数据库使用的时区的名称。美国/纽约是“东方”时间:它指定DST是什么时候,什么时候不是,以及与UTC的偏移量是什么。它甚至有历史数据,因为DST开始和结束的日期已经改变了。(在全球范围内,实际变化相当频繁。)政府(…)
保持非DST版本:
首先,让我们使用两个帮助函数:to_24hour (将(hour, ampm)转换为24小时格式)和to_12hour (另一种方式)。这将使事情更容易思考,因为我们可以更容易地在24小时内完成减法。
def to_24hour(hour, ampm):
"""Convert a 12-hour time and "am" or "pm" to a 24-hour value."""
if ampm == 'am':
return 0 if hour == 12 else hour
else:
return 12 if hour == 12 else hour + 12
def to_12hour(hour):
"""Convert a 24-hour clock value to a 12-hour one."""
if hour == 0:
return (12, 'am')
elif hour < 12:
return (hour, 'am')
elif hour == 12:
return (12, 'pm')
else:
return (hour - 12, 'pm')一旦我们有了这些,事情就变得简单了:
def time_in_24h(time,time_day): #time is eastern time
''' (number, str)--> number
This function converts a 12-hour time, represented by am/pm,to its equivalent 24-hour time.
Returns time in the 24-hour format.
'''
cCentral = 'Central Time(CT)' #-1 hour offset
mMountain = 'Mountain Time(MT)'#-2 hours offset
pPacific = 'Pacific Time(PT)'#-3 hours offset
eEst = 'EST is'
if time_day!='pm' and time_day!='am':
print('Input is not in the right format') #this is where input is not in the right format
return 0
else:
est_24hour = to_24hour(time, time_day)
hour, ampm = to_12hour((est_24hour - 1 + 24) % 24)
print(time, time_day, eEst, hour, ampm, cCentral)
hour, ampm = to_12hour((est_24hour - 2 + 24) % 24)
print(time, time_day, eEst, hour, ampm, mMountain)
hour, ampm = to_12hour((est_24hour - 3 + 24) % 24)
print(time, time_day, eEst, hour, ampm, pPacific)…在作出这些调整后:
>>> time_in_24h(1, 'pm')
1 pm EST is 12 pm Central Time(CT)
1 pm EST is 11 am Mountain Time(MT)
1 pm EST is 10 am Pacific Time(PT)最后一个音符。您的docstring如下:
(编号,str)-->数字 此函数将以上午/下午为代表的12小时时间转换为其等效的24小时时间。 以24小时格式返回时间。
当然,这就是to_24hour所做的。
时区意识
Python在时区方面并没有真正的帮助;Justin在另一个答案中建议pytz;这是一个很好的选择。
如果我们有一些我们知道在东部的日期或时间:
now = datetime.datetime(2014, 3, 14, 12, 34)抓取时区:
et = pytz.timezone('America/New_York')
ct = pytz.timezone('America/Chicago')
mt = pytz.timezone('America/Denver')
pt = pytz.timezone('America/Los_Angeles')我们可以转换为中环和其他有:
now_et = et.normalize(et.localize(now))
now_ct = ct.normalize(now_et.astimezone(ct))
now_mt = mt.normalize(now_et.astimezone(mt))
now_pt = pt.normalize(now_et.astimezone(pt))(正如注释所指出的,当更改可能跨越DST边界时,pytz会奇怪地要求调用normalize,这基本上就是您所做的任何事情。)
然后:
print('{} Eastern in various other timezones:'.format(now_et.strftime('%I %p')))
print('Central : {}'.format(now_ct.strftime('%I %p')))
print('Mountain: {}'.format(now_mt.strftime('%I %p')))
print('Pacific : {}'.format(now_pt.strftime('%I %p')))发布于 2014-03-16 12:47:38
如果您说的是时区,那么除了时间之外,还必须指定日期(年、月、日)。
要将给定的hours和am_or_pm转换为不同的时区,请执行以下操作:
time_in_24h不应该做太多的事情。让它做它的名字所暗示的,即:将输入小时、上午或下午转换为24小时格式:
def time_in_24h(hours, am_or_pm):
"""Convert to 24 hours."""
if not (1 <= hours <= 12):
raise ValueError("hours must be in 01,..,12 range, got %r" % (hours,))
hours %= 12 # accept 12am as 00, and 12pm as 12
am_or_pm = am_or_pm.lower()
if am_or_pm == 'am':
pass
elif am_or_pm == 'pm':
hours += 12
else:
raise ValueError("am_or_pm must be 'am' or 'pm', got: %r" % (am_or_pm,))
return hours您还可以使用strptime()实现它。
from datetime import datetime
def time_in_24h(hours, am_or_pm):
return datetime.strptime("%02d%s" % (hours, am_or_pm), '%I%p').hour然后,您可以定义print_times()函数,该函数在三个不同的时区中打印时间:
from datetime import datetime, time
import pytz
def astimezone(aware_dt, dest_tz):
"""Convert the time to `dest_tz` timezone"""
return dest_tz.normalize(aware_dt.astimezone(dest_tz))
def print_times(hours, am_or_pm, date=None, is_dst=None):
source_tz = pytz.timezone('US/Eastern')
# 2. add date
if date is None: # if date is not specified; use today
date = datetime.now(source_tz).date()
naive_dt = datetime.combine(date, time(time_in_24h(hours, am_or_pm), 0, 0))
# 3. create timezone-aware datetime object in the source timezone
source_dt = source_tz.localize(naive_dt, is_dst=is_dst)
#NOTE: these timezone names are deprecated,
# use Continent/City format instead
fmt = '%I %p %Z'
for tzname in 'US/Central', 'US/Mountain', 'US/Pacific':
dest_dt = astimezone(source_dt, pytz.timezone(tzname))
print("{source_dt:{fmt}} is {dest_dt:{fmt}} ({tzname})".format(
**locals()))重要的是正确指定日期,否则您将不知道正确的UTC偏移量。代码使用pytz模块访问时区信息。格式码用于打印。
示例:
>>> print_times(7, 'am')
07 AM EDT is 06 AM CDT (US/Central)
07 AM EDT is 05 AM MDT (US/Mountain)
07 AM EDT is 04 AM PDT (US/Pacific)
>>> print_times(1, 'pm')
01 PM EDT is 12 PM CDT (US/Central)
01 PM EDT is 11 AM MDT (US/Mountain)
01 PM EDT is 10 AM PDT (US/Pacific)
>>> print_times(9, 'pm')
09 PM EDT is 08 PM CDT (US/Central)
09 PM EDT is 07 PM MDT (US/Mountain)
09 PM EDT is 06 PM PDT (US/Pacific)特别说明:
datetime.now(source_tz)允许在给定时区中获得正确的当前时间。如果本地时区不是datetime.now(),则此处的source_tz将是不正确的。is_dst=None意味着tz.localize()方法会为不明确或不存在的本地时间引发异常。否则,它只是默认为is_dst=False,这可能不是您想要的tz.normalize()。发布于 2014-03-16 02:12:02
你可以试试pytz。您可以用pip install pytz安装它。在这里,您可以使用normalize方法(基于医生们)执行类似的操作:
>>> from datetime import datetime
>>> from pytz import timezone
>>> import pytz
>>> central = timezone('US/Central')
>>> mountain = timezone('US/Mountain')
>>> mountain_date = mountain.localize(datetime.now()) # set time as right now mountain time
>>> fmt = '%Y-%m-%d %I:%M:%S %p'
>>> central_date = central.normalize(mountain_date.astimezone(central))
>>> print central_date.strftime(fmt), central, 'is', mountain_date.strftime(fmt), mountain
2014-03-15 07:29:17 PM US/Mountain is 2014-03-15 08:29:17 PM US/Central因此,您的函数最终可能看起来如下所示:
>>> def time_in_24h(hour, am_pm):
"""hour is an integer that represents eastern time on the 12-hour clock, and am_pm
will take any string that begins with 'a' or 'p'"""
if not am_pm.lower().startswith(('a', 'p')): # return None if am_pm does not start with 'a' or 'p'
return
central = timezone('US/Central')
mountain = timezone('US/Mountain')
pacific = timezone('US/Pacific')
eastern = timezone('US/Eastern')
if hour == 12:
mod_hour = 0 if am_pm.lower().startswith('a') else 12
else:
mod_hour = hour + 12 if am_pm.lower().startswith('p') else hour # add 12 if am_pm starts with 'p', but keep original hour for display purposes
fmt = '%H:%M %p'
eastern_time = eastern.localize(datetime(1900, 1, 2, mod_hour))
for tz in (central, mountain, pacific):
d = tz.normalize(eastern_time.astimezone(tz))
print hour, am_pm, 'EST is', d.strftime(fmt), tz # tz displays as pytz timezone; can change
>>> time_in_24h(1, 'am')
1 am EST is 00:00 AM US/Central
1 am EST is 23:00 PM US/Mountain
1 am EST is 22:00 PM US/Pacific
>>> time_in_24h(9, 'pm')
9 pm EST is 20:00 PM US/Central
9 pm EST is 19:00 PM US/Mountain
9 pm EST is 18:00 PM US/Pacifichttps://stackoverflow.com/questions/22432030
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