我有一个带有ID (IP地址)和一个因素变量(Web浏览器)的表,我需要创建另一个表,该表对每个ID都有一个记录,还有一个因素变量的模式。我在想一些像SELECT ip, MODE (browser) FROM log GROUP BY ip这样的东西。
不幸的是,SQLite没有实现MODE函数,因此这是行不通的。我想用每个浏览器的计数构建一个临时表,然后使用SELECT DISTINCT ON或RANK ()语句,但是SQLite也不支持这些。
另外,在一个语句中这样做会更好,因为还有其他几个因素,我也需要它的模式(并且也按相同的ID分组)。
发布于 2014-03-11 21:00:03
要计算模式,请按browser列分组,获取每个组的COUNT(*),按该值排序,并以最大值获取记录。
如果您已经有了另一个组,请使用关联子查询:
SELECT ip,
(SELECT browser
FROM log AS log2
WHERE ip = ips.ip
GROUP BY browser
ORDER BY COUNT(*) DESC
LIMIT 1)
FROM (SELECT DISTINCT ip
FROM log) AS ips发布于 2018-12-01 20:48:07
有一个带有时间戳、标签和延迟的日志表。我们希望看到每个标签的延迟(发送时间: ST)模式( módusz )值,并按时间戳分组。一组数据值的模式是最常出现的值。
select L, T, avg( ST ) as MODEST, C
from (
select L, T, ST, count( ST ) as C
from (
select label as L,
substr( substr( timeStamp, 0, 8) || '00000000', 0, 14 ) as T,
latency as ST
from LOG
order by L, T, ST
) as XX
group by L, T, ST
) as YY
where L || '#' || T || '#' || C in ( select L || '#' || T || '#' || max(C)
from(
select L, T, count( ST ) as C
from (
select label as L,
substr( substr( timeStamp, 0, 8) || '00000000', 0, 14 ) as T,
latency as ST
from LOG
) as XX
group by L, T, ST ) as YY
group by L, T )
group by L, T, Chttps://stackoverflow.com/questions/22334714
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